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Umnica [9.8K]
4 years ago
5

Factor: -8x+16+8x8 – 31x2

Mathematics
1 answer:
ValentinkaMS [17]4 years ago
8 0

Answer:

- 2(4x -9)

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For a new customer, a video store charges $10 for a rental card plus $2 per movie. Using the linear equation (y=mx+b) you wrote,
netineya [11]

Given:

Charges for rental card = $10

Charges for movie = $2 per movie

To find:

The linear equation for given situation and find the cost to rent 6 movies.

Solution:

Let y be the total cost for x number of movies.

Cost of one movie = $2

Cost of x movies = $2x

Total cost = Charges for rental card + Charges for x movies

y=10+2x

Put x=6 to find the cost of 6 movies.

y=10+2(6)

y=10+12

y=22

Therefore, the total cost for a new customer to rent 6 movies is $22.

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3 years ago
Kevin saves 3/4 of the money he earns mowing yards each week. He earned $12.25 last week and $17.00 this week. How much will Kev
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The first week Kevin got 12.25 you divid that by 4 then multiply the answer by 3 and you do the same for the next week then you add them together to get your answer which should be $21.93
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4 years ago
According to a poll, 56% of voters support funding a new community center. A surveyor randomly selects 75 voters and asks each v
Debora [2.8K]

The probability of a person being a supporter of the new community center is 56% or 0.56.

<h2 /><h2>Given to us</h2>
  • 56% of voters support funding a new community center
  • A surveyor randomly selects 75 voters and asks each voter if he or she is in favor of the center.

<h2>To find</h2>

the probability of a success for this binomial experiment.

We want to know the probability of a single success for this experiment. therefore,

x=1

As given to us that 56% of the voters support funding the new community center, there, the probability of a person being a supporter is 0.56.

p=0.56

Thus, the probability of a person being a supporter of the new community center is 56% or 0.56.

Learn more about binomial distribution:

https://brainly.in/question/1640230

8 0
2 years ago
The middle 5 in 0.555 is 1/10 the value of the 5 to its
Marta_Voda [28]
Great, you know that. no need to ask more.
3 0
3 years ago
The students in Mr. Wilson's Physics class are making golf ball catapults. The
Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is 0 \leq x \leq 48.6\ ft and the range is 0 \leq y \leq 8.3\ ft

Step-by-step explanation:

we have

y=-0.014x^{2} +0.68x

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's  distance from the catapult in feet

y is the flight of the balls in feet

Part a)  How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-0.014x^{2} +0.68x=0

so

a=-0.014\\b=0.68\\c=0

substitute in the formula

x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}

x=\frac{-0.68(+/-)0.68} {(-0.028)}

x=\frac{-0.68(+)0.68} {(-0.028)}=0

x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

y=-0.014x^{2} +0.68x

Find out the derivative and equate to zero

0=-0.028x +0.68

Solve for x

0.028x=0.68

x=24.3

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint  between the x-intercepts

x=(0+48.6)/2=24.3\ ft

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

y=-0.014(24.3)^{2} +0.68(24.3)

y=8.3\ ft

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A  reasonable domain is the distance between the two x-intercepts

so

0 \leq x \leq 48.6\ ft

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A  reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

so

we have the interval -----> [0,8.3]

0 \leq y \leq 8.3\ ft

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0
3 years ago
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