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olga nikolaevna [1]
3 years ago
6

Please Help! If you give the right answer I will rate you 5/5

Mathematics
1 answer:
Aliun [14]3 years ago
7 0

Answer: There are 104 silvery minnow population in the Rio Grande River.

Step-by-step explanation:

Since we have given that

Number of tagged silvery minnows = 54

Number of captured silvery minnows = 62

It includes 12 tagged silvery minnows.

So, Number of silvery minnows without tags = 62 -12 =50

So, Good estimate of the silvery minnow population in the Rio Grande River would be

54+50\\\\=104

Hence, there are 104 silvery minnow population in the Rio Grande River.

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7 times as many as 9 is
Charra [1.4K]

Hi there! :)

<u><em>Answer:</em></u>

<u><em>=63</em></u>

<u><em>*The answer must have a positive sign.*</em></u>

Step-by-step explanation:

Product it's going to be multiply by the numbers, fractions, decimals, factors, and multiples.

First, you multiply by the numbers.

7*9=63

9*7=63

Then you can also divide by the numbers.

63/7=9

63/9=7

Final answer: → =63

63 times.

Hope this helps!

Thanks!

-Charlie

Have a great day!

:)

:D

3 0
3 years ago
V(x) is a function<br> A. True<br> B. False<br> 100 points
mash [69]

Answer:

true

Step-by-step explanation:

4 0
3 years ago
A lioness has 4 cubs that weigh 1.7 kg, 2.1 kg, 3 kg, and 2.7 kg. Each cub eats 1.25 kg of food a
Vladimir [108]

Answer:

2.375

Step-by-step explanation:

( 1.7 kg+2.1 kg+3 kg+ 2.7 kg)/4=2.375

8 0
3 years ago
Read 2 more answers
Consider a population list x with μx=10 and SDx = 1. A second population list, y, with μy=10 and SDy=2, is added to the first li
Basile [38]

Answer:

The combined standard deviation is 1.58114.

Step-by-step explanation:

The formula to compute the combined standard deviations of two different data sets is:

SD_{c} =\sqrt{\frac{n_{X}S^{2}_{X}+n_{2}S^{2}_{Y}+n_{X}(\mu_{X}-\mu_{c})^{2}+n_{Y}(\mu_{Y}-\mu_{c})^{2}}{n_{X}+n_{Y}}

Here \mu_{c} is the combined mean given by:

\mu_{c}=\frac{n_{X}\mu_{X}+n_{Y}\mu_{Y}}{n_{X}+n_{Y}}

It is provided that the sample size is same for both the data sets, i.e.n_{X} = n_{Y}=n

Compute the combined mean as follows:

\mu_{c}=\frac{n_{X}\mu_{X}+n_{Y}\mu_{Y}}{n_{X}+n_{Y}}\\=\frac{(n\times10)+(n\times10)}{n+n}}\\=\frac{20n}{2n}\\ =10

Compute the combined standard deviation as follows:

SD_{c} =\sqrt{\frac{n_{X}S^{2}_{X}+n_{2}S^{2}_{Y}+n_{X}(\mu_{X}-\mu_{c})^{2}+n_{Y}(\mu_{Y}-\mu_{c})^{2}}{n_{X}+n_{Y}}}\\=\sqrt{\frac{(n\times1^{2})+(n\times2^{2})+(n(10-10))+(n(10-10))}{n+n}}\\=\sqrt{\frac{n+4n}{2n} } \\=\sqrt{\frac{5n}{2n} } \\=\sqrt{\frac{5}{2}} \\=1.58114

Thus, the combined standard deviation is 1.58114.

3 0
3 years ago
Solve for p in the literal equation 4p + 3r =9.<br> p=
yan [13]

Answer:

p= 9/4 - 3r/4

Step-by-step explanation:

Move 3r to the right and when you divide 4 from both sides and each variable, you are left with p= 9/4 - 3r/4 since you cannot simplify it more.

4 0
4 years ago
Read 2 more answers
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