Question

Andre and Morgan are both headed to Florida for vacation. Andre will drive 70 miles per hour. Morgan will drive 55 miles per hour but will leave 3 hours earlier than Andre. How many hours will Morgan have been driving before Andre catches up with her?

Answer 1

Answer:

The number of hours Moran wold have driven before Andre catches up with him is 14 hours

Step-by-step explanation:

The given information are;

The speed with which Andre will drive = 70 miles per hour

The speed with which Morgan will drive = 55 miles per hour

The time of departure of Morgan = 3 hours before Andre departs

Let the time at which Andre catches up with Morgan be, t

We have, from the definition of distance traveled;

Distance traveled =Speed × Time

The distance Morgan would have driven in t hours = 55 × t

Given that to catch up with Morgan, Andre has to travel the same distance, and that Andre starts 3 hours late, we have;

The distance Andre would  drive when Morgan has driven for t hours = 70 × (t - 3)

Therefore, since the distance at the point they meet is the same distance for them both, we have;

55 × t = 70 × (t - 3)

55 × t = 70 × t - 210

210 = 70 × t - 55 × t  = 15 × t

t = 210/15 = 14 hours

Therefore, Morgan would have driven for 14 hours before Andre catches uo with him.