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2 years ago

Which point satisfies both ƒ(x) = 2x and g(x) = 3x?

Mathematics

2 answers:

ki77a [65]2 years ago

7 0

The answer would be. 0,0

siniylev [52]2 years ago

4 0

Answer:

(0,0)

Step-by-step explanation:

If a point satisfies both functions, they must be equal to each other. Thus, we have:

$f(x)=g(x)$

$2x=3x$

The only x that satisfies this is 0.

Therefore, the y is also zero.

The point is (0,0).

Alternatively, you can also visualize the graphs. The only point where the graphs will touch is the origin point or (0,0).

You might be interested in

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0

2 years ago

Please help, the word cut off is slope: 3

Sidana [21]

Answer:

1. y=3x-2

2. y=-1/4x+5

These equations are in slope-intercept form (y=mx+b). IN this equation m represents the slope and b represents the y intercept. Therefore, y=3x-2 and y=-1/4x+5 are correct

Step-by-step explanation:

6 0

2 years ago

Solve the system of linear equations using the Gauss-Jordan elimination method.

mixas84 [53]

Answer:

x = -0.6

y = 2.2

z = 2

Step-by-step explanation:

2x + y - 2z = -3

x + 3y - z = 4

3x + 4y - z = 5

Rewrite the system in matrix form and solve it by Gaussian Elimination (Gauss-Jordan elimination)

2 1 -2 -3

1 3 -1 4

3 4 -1 5

R1 / 2 → R1 (divide the 1 row by 2)

1 0.5 -1 -1.5

1 3 -1 4

3 4 -1 5

R2 - 1 R1 → R2 (multiply 1 row by 1 and subtract it from 2 row); R3 - 3 R1 → R3 (multiply 1 row by 3 and subtract it from 3 row)

1 0.5 -1 -1.5

0 2.5 0 5.5

0 2.5 2 9.5

R2 / 2.5 → R2 (divide the 2 row by 2.5)

1 0.5 -1 -1.5

0 1 0 2.2

0 2.5 2 9.5

R1 - 0.5 R2 → R1 (multiply 2 row by 0.5 and subtract it from 1 row); R3 - 2.5 R2 → R3 (multiply 2 row by 2.5 and subtract it from 3 row)

1 0 -1 -2.6

0 1 0 2.2

0 0 2 4

R3 / 2 → R3 (divide the 3 row by 2)

1 0 -1 -2.6

0 1 0 2.2

0 0 1 2

R1 + 1 R3 → R1 (multiply 3 row by 1 and add it to 1 row)

1 0 0 -0.6

0 1 0 2.2

0 0 1 2

x = -0.6

y = 2.2

z = 2

7 0

3 years ago

The variables x and y are directly proportional, and y = 2

ololo11 [35]

3/2 = 9/x,

so 9 times 2 divided by 3 = 6

A: 6

5 0

3 years ago

!! Plss help me!! ASAP!! I will give you BRAINLYEST!!!

MrMuchimi

31.4 cm

Step-by-step explanation:

the radius is 5 so the diameter is 10 so you'll have to multiply 3.14 by 10 not 5

5 0

2 years ago