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Answer:
y = 6 + 4x
After 4 years, the tree would be 22 ft tall.
Step-by-step explanation:
Hi there!
Let x = the number of years that pass
Let y = the height of the tree (ft)
We're given that the 6-foot tree grows at a rate of 4 ft per year. This means that the height of the tree will be equal to 6 ft, the original height, plus another 4 ft every year that passes.
Height of tree = 6 feet + 4 feet × number of years that pass
y = 6 + 4x
To solve for how tall the tree would be 4 years after Dina plants it, replace x with 4, since 4 years have passed:
y = 6 + 4(4)
y = 6 + 16
y = 22
Therefore, the tree would be 22 ft tall.
I hope this helps!
Answer:
below
Step-by-step explanation:
1) slope = rise / run
2 coordinates are (-4, 0), (0, 2).
2 - 0 = 2
0 -- 4 = 4
2 / 4 = 1/2 so the slope is 0.5 or ½
2) it crosses the y axis at the average of the origin and 4.
4 + 0 = 4 / 2 = 2 so y intercept is 2.
3) in y= mx + b form
f(x) = ½x + 2, or, f(x) = 0.5x + 2
Using the law of cosines and sines, the measure of angle B is: 38.4°.
<h3>What is the Law of Cosines and Sines?</h3>
Law of cosines is: c = √[a² + b² ﹣ 2ab(cos C)]
Law of sines is: sin A/a = sin B/b = sin C/c
Use the law of cosines to find c:
c = √[12² + 18² ﹣ 2(12)(18)(cos 117)]
c ≈ 25.8
Use the law of sines to find angle B:
sin B/b = sin C/c
sin B/18 = sin 117/25.8
sin B = (sin 117 × 18)/25.8
sin B = 0.6216
B = sin^(-1)(0.6216)
B = 38.4°
Learn more about the law of cosines on:
brainly.com/question/23720007
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15 is coefficient, a is a variable, 2 and -7 are like terms, 15a is a term and 2 and 7 are constants.
