Answer:
Given a square ABCD and an equilateral triangle DPC and given a chart with which Jim is using to prove that triangle APD is congruent to triangle BPC.
From the chart, it can be seen that Jim proved that two corresponding sides of both triangles are congruent and that the angle between those two sides for both triangles are also congruent.
Therefore, the justification to complete Jim's proof is "SAS postulate"
Step-by-step explanation:
Answer:
![E[R]](https://tex.z-dn.net/?f=E%5BR%5D)
= 99 Ω
= 2.3094 Ω
P(98<R<102) = 0.5696
Step-by-step explanation:
The mean resistance is the average of edge values of interval.
Hence,
The mean resistance, ![E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}](https://tex.z-dn.net/?f=E%5BR%5D%20%3D%20%5Cfrac%7Ba%2Bb%7D%7B2%7D%20%20%3D%20%5Cfrac%7B95%2B103%7D%7B2%7D%20%3D%20%5Cfrac%7B198%7D%7B2%7D)
= 99 Ω
To find the standard deviation of resistance, we need to find variance first.
Hence,
The standard deviation of resistance, 
= 2.3094 Ω
To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.
From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696
3 multiples of 10 that have 3 in them are 30, 300, and 3000
Okay lets get started.
I drove 110 miles with speed of 55 mi/hr so the time taken =
time = distance / speed
time = 110 / 55 = 2 hrs For the distance which is covered with 55 mi/hr speed.
Total time for reaching home is 4 hrs 15 minutes. (given in question)
Means rest distance after snow is covered in = 4 hrs 15 minutes - 2 hrs
= 2 hrs 15 minutes = 2 + 15/60 = 2.25 hrs
The speed in snow driving is 35 mi/hr
So distance covered in snow driving is = 2.25 * 35 = 78.75 miles
Hence the total distance = 110 + 78.75 = 188.75 miles : Answer
Hope that will help :)
3x moved 3 units to the left, -5y moved 14 units to the right.
