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Answer 1

Answer:

$D.\ \angle FOB\ and\ \angle EOC$

Step-by-step explanation:

$\angle FOC=180\textdegree\ \ \ \ \ \ \ \ \ \ as\ FOC\ is\ a\ straight\ line\\\\\angle FOC=\angle COE+\angle EOF\\\\\angle COE+\angle EOF=180\textdegree\\\\Hence\ \angle COE\ is\ supplementary\ to\ \angle EOF$

$\angle EOB=180\textdegree\ \ \ \ \ \ \ \ \ \ as\ EOB\ is\ a\ straight\ line\\\\\angle EOB=\angle FOB+\angle EOF\\\\\angle FOB+\angle EOF=180\textdegree\\\\Hence\ \angle FOB\ is\ supplementary\ to\ \angle EOF$