Question

an unknown charge exerts an attractive force of 4.23 E 13 N. If these charges are separated by 8cm, what is the magnitude of the unknown charge if the other charge has a magnitude of 10C

Answer 1

Answer:

Since there is attraction force between two charges so the other charge must be - 3C

Explanation:

As we know that the force between two charges is given by formula

$F = \frac{kq_1q_2}{r^2}$

here we know that

$F = 4.23 \times 10^{13}N$

also we know that

$q_1 = 10C$

r = 8 cm

now we have

$4.23 \times 10^{13} = \frac{(9\times 10^9)(10)q}{0.08^2}$

so we have

$q = -3C$