Answer:
<h3>The area of second coil is ≅ 0.025Explanation:
Given :
No. of turns in the first coil
No. of turns in the second coil
Area of first coil
According to the law of electromagnetic induction,
Induced emf =
Where magnetic flux.
Since given in question emf of both coil is same so we compare above equation.
Therefore, the area of second coil is ≅ 0.025
Answer:
T_2= 234.37 K
Explanation:
According to Claperyon, we know that
P_1= Atmospheric pressure 760 mm Hg
P_2 = pressure at the bottom of the column
= 10×10^3 mm of Hg+ 760 mm of Hg
= 10760 mm of Hg
now,
P_2-P_1= 10760-760= 10^4 mm
P_2-P_1 ( in pascals) = 10^4× 133.322= 1333220 mm
the enthalpy of fusion (ΔH-fus) of mercury is 2.292 KJ/mol
use the above equation to calculate ΔT as follows
therefore, T_2= 234.37 K