Question

A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A constant tangential force of 290 N applied to its edge causes the wheel to have an angular acceleration of 0.816 rad/s2. (a) What is the moment of inertia of the wheel? kg

Answer 1

Answer:

Explanation:

Torque produced = tangential force x radius

= 290 x .33

= 95.7 N.m

angular acceleration = Torque / moment of inertia

.816 = 95.7 / moment of inertia

moment of inertia = 95.7 / .816

= 117.28 kgm².