Answer:
D. no solution
Step-by-step explanation:
h-z=3(1)
h=3+z(minus z from both side)
put in the second equation
-3h,+3z=6(2)
-3(3+z)+3z=6
-9-3z+3z=6
-9=6( not true)
so the equation doesn't have a solution.
Observe the given data distribution table carefully.
The 5th class interval is given as,
The upper limit (UL) and lower limit (LL) of this interval are,
Thus, the upper-class limit of this 5th class is 17.4.
Round each coin weight to the nearest gram first, penny 3g, nickel 5g, dime 2g, quarter 6g, half dollar 11g. Now add those numbers together as he has one of each coin 3+5+2+6+11=27 grams
Answer:
yess queen
Step-by-step explanation:
why not
