Since the two objects are connected by the same rope, how much tension is pulling on the 500g mass

All of the following are benefits of statistics except that it __________. A. increases knowledge B. promotes change C. creates

erastovalidia [21]

C. creates biases
this is the only answer that would be a disadvantage.

5 0

3 years ago

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A very long cylinder, of radius a, carries a uniform polarization P perpendicular to its axis. Find the electric field inside th

Juliette [100K]

Answer:

For electric field inside cylinder, check image 02 attached

For electric field outside cylinder, check image 03 attached

Explanation:

Let's consider the polarized cylinder as superposition of two cylinders with opposite,equal, uniform charge densities in a way shown in the figure in the "image 01"d attached ;

In general, if we have an object with polarization (P¬) , then we have to take two objects with similar shape to the system, with opposite, equal, and uniform charge densities and then we super-impose these two objects in such a way that the total dipole moment of this superimposed system is equal to the total dipole moment of original system.

Now, we can take the super- imposed system as equivalent to the original system for calculating electric field and potential.

Therefore,

For the electric field inside the cylinder, check the solution in "image 02" i attached

For the electric field outside the cylinder, check, "image 03" i attached.

4 0

3 years ago

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A wheel of radius R = 0.80 m is pulled by a rope looped around a frictionless axle. The total mass of the wheel and axle assembl

iragen [17]

Answer:

$\frac{K_T}{K_R}=\frac{600J}{188.63J}=3.18$

Explanation:

To find the rotational kinetic energy you first calculate the angular acceleration by using the following formula:

$\tau=I\alpha\\\\FR=I\alpha\\\\\alpha=\frac{FR}{I}$

F: force applied

R: radius of the wheel

I: moment of inertia

$\alpha=\frac{(120N)(0.80m)}{26.88kgm^2}=3.57\frac{rad}{s^2}$

With this value you calculate the angular velocity:

$\omega^2=\omega_o^2+2\alpha \theta\\$

you calculate how many radians the wheel run in 5.0m

$\theta=\frac{2\pi (0.8m)}{5.0m}=\approx1.00rad$

$\omega=\sqrt{2(3.57\frac{rad}{s^2})(1.00rad)}=2.67\frac{rad}{s}$

Next, you use the formula for the rotational kinetic energy:

$K_R=\frac{1}{2}I\omega^2=(26.88)(2.67)^2 J = 188.63J$

For the transnational kinetic energy you use the following equation:

$W=\Delta K_T$ (net work equals the change in the kinetic energy).

By replacing the you obtain:

$\Delta K_T=Fd=(120)(5.0)J=600J$

Finally, the ratio between translational rotational kinetic energy is:

$\frac{K_T}{K_R}=\frac{600J}{188.63J}=3.18$

hence, translational kinetic energy is three times the rotational kinetic energy.

6 0

3 years ago

A father (mF = 85 kg) and his daughter (mD= 45 kg) stand on a flat frozen lake of negligible friction. They hold a 14 m long r

mr Goodwill [35]

Answer:

4.84615 m

Explanation:

Here the linear momentum is conserved and it is assumed that they will meet at the center of gravity of the system.

The center of gravity is given by

$R=\frac {1}{M}\sum _{i=1}^{n}m_ir _i$

where

i = Particle

m = Mass

r = Position

n = Number of particles

The father's location is taken as reference

$R=\frac{(0\times 85)+(45\times 14)}{85+45}=4.84615\ m$

The father will be 4.84615 m from the origin.

7 0

3 years ago

What is the Archimedes Principle and how does it relate to the Plimsoll Line?

Citrus2011 [14]

$\huge\fbox \pink{a}ns \huge\fbox \green{w} \huge\fbox \red{e} r$

Archimedes' principle states: An object immersed in a fluid experiences a buoyant force that is equal in magnitude to the force of gravity on the displaced fluid.
The PLIMSOLL LINE marked on the body of the ship acts as a guideline to ensure that the ship is loaded within the safety limit. A ship submerge lower in fresh water as fresh water density is lesser than sea water. Ships will float higher in cold water as cold water has a relatively higher density than warm water.

6 0

3 years ago

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