Answer:
Part a)
Final speed of the corn is 19.05 m/s
Part b)
Kinetic energy of the corn is 3.1 J
Explanation:
Part a)
As we know that the initial position of the corn is
h = 18.5 m
now we also know that it will fall from rest and moving under constant acceleration so we will have
Part b)
Kinetic energy of the corn is given as
Answer:
Here , mass of bucket ,m = 3.2 Kg
Now , let the tension in upper rope is T1
the tension in the middle rope is T2
a)
For lower bucket, balancing forces in vertical direction
T2 - mg = 0
T2 = mg
T2 = 3.2 *9.8
T2 = 31.36 N
tension in the middle rope is 31.36 N
For the upper bucket , balancing forces in vertical direction
T1 - T2 - mg = 0
T1 = T2 + 3.2 *9.8
T1 = 62.72 N
the tension in the upper rope is 62.72 N
B)
for a = 1.25 m/s^2
Using second law of motion ,for both the buckets
Fnet = ma
T1 - 2mg = 2m*a
T1 = 2*3.2*(9.8 +1.25)
T1 = 70.72 N
the tension in the upper rope is 70.7 N
Now , the lower bucket
Using second law of motion,
T2 - mg = ma
T2 = 3.2 * (9.8 + 1.25)
T2 = 35.36 N
the tension in the lower rope is 35.36 N
Answer:
PE=mgh
KE=<u>1</u> mv²
2
hope its helpful for u ..
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Answer:
Q=∆U+W
Explanation:
work done+ change in internal energy = heat supplied to change the internal energy
(1st law of thermodynamics)
