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krok68 [10]
3 years ago
13

The prismatic bar has a cross-sectional area

Physics
1 answer:
ludmilkaskok [199]3 years ago
8 0

solution:

sum fx=0\\
n=\frac{1}{2}\times\frac{w_{0}}{a}(2a-x)^2\\
n=\frac{w_{0}}{20}(2a-x)^2\\
angle is the normal shus\\
\sigma =\frac{N}{A}\\
\frac{\frac{w_{0}}{2a}(2a-x)^2}{A}\\
\sigma(x)=\frac{w_{0}}{2aA}[2a-x]^2

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A 42 Watt light bulb is connected to a 12 volt source of potential
abruzzese [7]

Answer:

The natural medium emanating from the Sun and other very hot sources (now recognised as electromagnetic radiation with a wavelength of 400-750 nm), within which vision is possible.

Explanation:

just the way it is

8 0
4 years ago
Say you want to make a sling by swinging a mass M of 1.7 kg in a horizontal circle of radius 0.048 m, using a string of length 0
DENIUS [597]

Answer:

Tension in the string is equal to 58.33 N ( this will be the strength of the string )

Explanation:

We have given mass m = 1.7 kg

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So \frac{1}{2}\times 1.7\times v^2=14

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v = 4.05 m/sec

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3 0
3 years ago
Which of the following is typically NOT a method scientist use to determine astronomic distances
tangare [24]
I think the answer is A
5 0
3 years ago
Why is it sometimes difficult for scientists to identify a a fold or fault?
Sauron [17]

Folds and faults are difficult to identify because they occur in the interior of rocks and also due to the dense nature of the materials.

<h3>What are faults and folds?</h3>

Faults are lines of weakness are present in materials dues to uneven positioning of the particles of the material.

Folds occurs when infolds occur in materials.

Faults and folds usually occur in rocks.

Folds and faults are difficult to identify because they occur internally and also due to the dense nature of the materials.

Learn more about faults and folds at: brainly.com/question/14240712

4 0
2 years ago
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Answer:

{ \bf{average \: velocity =  \frac{15 + 40}{2}}} \\   = 27.5 \:  {ms}^{ - 1}  \\  { \bf{acceleration =  \frac{v - u}{t} }} \\  =  \frac{40 - 15}{10}  \\  = 2.5 \:  {ms}^{ - 2}  \\  \\ { \tt{second \: qn : }} \\ { \bf{final \: velocity =u + at }} \\ v = 0 + (5 \times 10) \\  = 50 \:  {ms}^{ - 1}

5 0
3 years ago
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