Question

The prismatic bar has a cross-sectional area

Answer 1

solution:

$sum fx=0\\ n=\frac{1}{2}\times\frac{w_{0}}{a}(2a-x)^2\\ n=\frac{w_{0}}{20}(2a-x)^2\\ angle is the normal shus\\ \sigma =\frac{N}{A}\\ \frac{\frac{w_{0}}{2a}(2a-x)^2}{A}\\ \sigma(x)=\frac{w_{0}}{2aA}[2a-x]^2$