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krok68 [10]
3 years ago
13

The prismatic bar has a cross-sectional area

Physics
1 answer:
ludmilkaskok [199]3 years ago
8 0

solution:

sum fx=0\\
n=\frac{1}{2}\times\frac{w_{0}}{a}(2a-x)^2\\
n=\frac{w_{0}}{20}(2a-x)^2\\
angle is the normal shus\\
\sigma =\frac{N}{A}\\
\frac{\frac{w_{0}}{2a}(2a-x)^2}{A}\\
\sigma(x)=\frac{w_{0}}{2aA}[2a-x]^2

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Where the bold letters indicate vectors, a is the acceleration, v the velocity and t the time

Analyzing this expression we see that for there to be a change in velocity, there must be an acceleration of the body.

Let's analyze the different claims

1. True. If it is stopped and you start to move there is an acceleration, therefore there is a change in speed, but after you are moving the acceleration becomes zero and there is no change in speed

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5. False. If you change the direction at the instant of change there is an acceleration but after you go in the opposite direction there is not acceleration therefore there is no change in speed.

In conclusion using the definition of acceleration in kinematics, we can find the answer the condition for a change in velocity, the correct statement is:

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