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rosijanka [135]
3 years ago
12

Iliana wants to find the perimeter of triangle ABC. She uses the distance formula to determine the length of AB. Finish Iliana’s

calculations to find the length of AB.
What is the perimeter of triangle ABC? Round the answer to the nearest tenth, if necessary.

10 units
11 units
12 units
13 units

Mathematics
2 answers:
8090 [49]3 years ago
5 0
The hypotenuse is 5, the sides are 3 and 4. The perimeter is the addition of those 3 numbers.
5+4+3 = 12 units

For future reference, if the sides of a right triangle are any multiples of 3 and 4, the hypotenuse is the same multiple of 5. This triangle has sides with lengths 3, 4, and 5, and a triangle with sides 9 and 12 would have a hypotenuse of 15 :)

Mars2501 [29]3 years ago
5 0

Answer:

12 units

Step-by-step explanation:

I just took the test

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(-35-42-63)/7= (-140)/7=-20

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This year 426,731 people visited a water park.last year 102,865 fewer people visited the park the year the park opened 84,007 fe
mylen [45]

Answer:

236,859 people visited the water park the year it opened.

Step-by-step explanation:

426,731 - 102,865= 323,866 the amount of people that visited last year

323,866 - 87,007 = 236,859 the amount of people that visited the water park the year it opened

7 0
3 years ago
Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the
kodGreya [7K]

Answer:

  • p=0.7103 (4-game series)
  • p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters  n=4, p=0.6:

P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\  i=4,5,6,7

#We find probabilities for the different values of i:

P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659

Hence, probability of the stronger team winning overall is:

=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103

#Define Y as the random variable for winning 2/3 games.:

P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0
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Lyrx [107]

Answer:

the difference:  $2,192.64

Step-by-step explanation:

After 1 year, the truck has lost 8% of its value:  v(x) = $32,500(0.92)^1, or

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After 2 years, v(x) = $32,500(0.92)^2, or $27,500.  Finally, after 3 years,

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Subtracting $25,307.36 (the value after 3 years) from $27,500 (the value after 2 years) yields the difference:  $2,192.64

6 0
3 years ago
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