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rosijanka [135]
3 years ago
12

Iliana wants to find the perimeter of triangle ABC. She uses the distance formula to determine the length of AB. Finish Iliana’s

calculations to find the length of AB.
What is the perimeter of triangle ABC? Round the answer to the nearest tenth, if necessary.

10 units
11 units
12 units
13 units

Mathematics
2 answers:
8090 [49]3 years ago
5 0
The hypotenuse is 5, the sides are 3 and 4. The perimeter is the addition of those 3 numbers.
5+4+3 = 12 units

For future reference, if the sides of a right triangle are any multiples of 3 and 4, the hypotenuse is the same multiple of 5. This triangle has sides with lengths 3, 4, and 5, and a triangle with sides 9 and 12 would have a hypotenuse of 15 :)

Mars2501 [29]3 years ago
5 0

Answer:

12 units

Step-by-step explanation:

I just took the test

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He can either measure the third side length, apply the Pythagorean theorem to find the height of the triangle, and then calculate the area, or he can find the measure of the included angle between the  known side lengths and use trigonometry to express the height of the triangle and then determine the

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3 years ago
There is a spinner with 15 equal areas, numbered 1 through 15. If the spinner is spun
Brrunno [24]

Answer:

1/3 and 1.5

Step-by-step explanation:

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15

There are 5 Multiples of 3 on the Spinner and 3 multiples of four.

5/15 is the probability for a multiple of 3 which can be simplified to 1/3

3/15 is the probability for a multiple of 4 which can be simplified to 1/5

Hope this Helps!

5 0
4 years ago
If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta
iren [92.7K]
\sin\theta= \frac{4}{5} 
\\
\\\sin^2\theta+\cos^2\theta=1
\\ \cos\theta=\pm \sqrt{1-\sin^2\theta} =\pm \sqrt{1-( \frac{4}{5})^2 } =\pm \sqrt{1- \frac{16}{25} } =\pm \sqrt{\frac{9}{25} }=\pm \frac{3}{5}}

\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-\frac{3}{5}

\cot\theta= \frac{\cos\theta}{\sin\theta}= \frac{-\frac{3}{5}}{\frac{4}{5}}  =- \frac{3}{4}

5 0
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X=1 & Y=12
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