Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Answer:
The bottom table.
Step-by-step explanation:
It's the only one that shows options for heads and tails for every number.
15 sandwiches
3 tomatoes= 5 sandwiches.
So if there's 9, that makes 3 groups of 3 tomatoes which would make 3x5 or 5+5+5 ;-;
15.
The first thing you should do for this case is to use the following table to perform the equation of a line:
y x
41,431 1995
48,729 2005
We have then that the line that best fits this data is
y = 729.8x - 1E + 06
Then, to know in what year the number of shopping centers reaches 80,000 we must replace this number in the equation of the line and clear x:
80000 = 729.8x - 1E + 06
Clearing x
x = (80000 + 1E + 06) / (729.8) = 1479.857495
nearest whole number
1480
This means that after 1480 years, 80000 shopping centers are reached.
Equivalently, this amount is reached in the year:
1480 + 1995 = 3475
In the year 3475
answer
(a) y = 729.8x - 1E + 06
(b) In the year 3475
