Find the circumference and the area Of the circle with diameter 9ft
1 answer:
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Long leg = 8 → opposite
short leg = 6 → adjacent
hypotenuse = ?
8² + 6² = c²
64 + 36 = c²
100 = c²
√100 = √c²
10 = c
sin ∠BOC = opposite / hypotenuse
sin ∠BOC = 8 / 10
sin ∠BOC = 0.80
tan ∠BOC = opposite / adjacent
tan ∠BOC = 8 / 6
tan ∠BOC = 1.33
short leg = 6 → adjacent
hypotenuse = ?
8² + 6² = c²
64 + 36 = c²
100 = c²
√100 = √c²
10 = c
sin ∠BOC = opposite / hypotenuse
sin ∠BOC = 8 / 10
sin ∠BOC = 0.80
tan ∠BOC = opposite / adjacent
tan ∠BOC = 8 / 6
tan ∠BOC = 1.33
Think of the two pieces together as a single cone of height 19, and its volume.
Then think of only the upper piece as a cone, and find its volume.
The volume of the frustum is the total volume minus the volume of the upper piece.
The volume of a cone is:
Total volume:
Volume of upper cone:
Volume of frustum:
Then think of only the upper piece as a cone, and find its volume.
The volume of the frustum is the total volume minus the volume of the upper piece.
The volume of a cone is:
Total volume:
Volume of upper cone:
Volume of frustum: