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AlexFokin [52]
3 years ago
7

a section of hollow pipe and a solid cylinder have the same radius, mass, and length. they both rotate about their long central

axes with the same angular speed. which object has the higher rotational kinetic energy?
Physics
1 answer:
kifflom [539]3 years ago
4 0

Answer:

Teniendo dos tuberías, una hueca y otra sólida, con la misma masa, radio y longitud, ambas poseen la misma rapidez angular, entonces el cuerpo hueco tendrá mayor energía cinética rotacional que la tubería sólida, esto es debido a que el tubo hueco tiene mayor inercia rotacional.

La ecuación de energía rotacional viene dada como:

Er = (1/2)·I·ω

De esta manera tenemos que el tubo hueco tiene mayor inercia rotacional que el tubo sólido, por ende, mayor energía.

Explanation:

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BRAINLIEST!
Vlada [557]

The two tests used for measuring each of the following fitness areas are as follows:

     a) Cardiorespiratory fitness → The 2.4 km run test; Astrand treadmill test

     b) Muscle strength → Muscle Testing Scale,  Bench/Leg press

     c) Body Composition → DEXA Scan, Bioelectrical Impedance Analysis

      Cardiorespiratory fitness is the ability of the circulatory as well as the respiratory systems to deliver oxygen to the mitochondria of skeletal muscle for energy generation during physical activity.

     

      Cardiorespiratory fitness is a vital indicator of both physical and mental wellbeing. It can lower the chance of developing heart disease and type 2 diabetes. Cardiorespiratory fitness improves lung and heart health while also increasing emotions of well-being.

  • The astrand treadmill test is used widely for testing the fitness of cardiorespiratory. The usefulness of this test is used to assess a client's aerobic fitness.
  • The 2.4 km run test is an uncomplicated running test that needs the use of a stopwatch and a running track. It is widely used for aerobic fitness

      Muscle strength refers to the capacity to move and lift items.  It is determined by the amount of power you can exert and the amount of weight you can lift within a short amount of time.

   

      The test used to determine the muscle strength can be:

  • Muscle Testing Scale;
  • Bench/Leg Press

     

     Muscular strength testing is used to examine a complaint of weakness, which is common when there is a suspectable neurologic illness or muscle imbalance.

 

      Bench presses are weight-training exercises that can be added to your routine to help increase upper body strength and improve muscular endurance.

      Body Composition relates to the bones, muscles, and body fat in the body. Body physique composition is used by medical professionals to determine if you are at a healthy weight for your specific body.

       The test used to determine the body Composition can be:

  • DEXA Scan
  • Bioelectrical Impedance Analysis  

        Dexa Scan scans your body using x-ray technology to offer a thorough evaluation of the amount of muscle mass and fat mass your body contains, as well as where fat and muscle are deposited or stored on your body.

        Bioelectrical Impedance Analysis evaluates fat-free mass by passing a low electric current across the body. Because electricity can only move by water, and each body tissue includes variable quantities of water, the conductivity of each tissue type influences the flow of the electric current. 

Therefore, from the above explanations, we can conclude that we've clearly understood the various test for each fitness area.

Learn more about body fitness here:

brainly.com/question/10033432?referrer=searchResults

       

8 0
3 years ago
The Sun has a mass of 1.99x10^30 kg and a radius of 6.96x10^8 m. Calculate the acceleration due to gravity, in meters per second
just olya [345]

Answer:

g=274\ m/s^2

Explanation:

Mass of the Sun, M=1.99\times 10^{30}\ kg

The radius of the Sun, r=6.96\times 10^8\ m

We need to find the acceleration due to gravity on the surface of the Sun. It is given by the formula as follows :

g=\dfrac{GM}{r^2}\\\\g=\dfrac{6.67\times 10^{-11}\times 1.99\times 10^{30}}{(6.96\times 10^8)^2}\\\\g=274\ m/s^2

So, the value of acceleration due to gravity on the Sun is 274\ m/s^2.

8 0
3 years ago
Please answer !!!A company wants to install a sensor to monitor the light level in the offices of their buildings. The sensor co
vovikov84 [41]

Answer:

Explanation:

The sensor contains an LDR which has a resistance of 10kohlms in daylight and 100kohlms in the dark.

If the resistor in the circuit is 1 megaohlm, the total resistance in daylight and darkness will be 1.01 megaohms and 1.1 megaohlms.

The percentage difference = (1.1-1.01)/1.1*100% = 8.18%

If the resistor in the circuit is 25 kohlm, the total resistance in daylight and darkness will be 35 kohms and 125 kohlms.

The percentage difference = (125-35)/125*100% = 72%

With the input p.d to the sensing circuit fixed at 12 v, the sensing current will change according to the total resistance. A 72% difference is much more detectable. So the 25 kohm resistor is the better choice.

3 0
3 years ago
Read 2 more answers
A ball is launched up a semicircular chute in such a way that at the top of the chute, just before it goes into free fall, the b
Mariulka [41]

We have centripetal acceleration = v^2/r = 2g

So, v = \sqrt{2gr}

Now by equation of motion we have S= ut +0.5at^2

S =displacement, u = initial velocity, a= acceleration and t = time

Here S =  2r and a = g , u = 0

2r = 0+\frac{1}{2} *g*t^2

t = \sqrt{\frac{4r}{g} }

Distance traveled in horizontal direction = \sqrt{2gr}*\sqrt{\frac{4r}{g} }= \sqrt{8r^2} =2r\sqrt{2}

8 0
4 years ago
A 10-μF capacitor in an LC circuit made entirely of superconducting materials ( R = 0 Ω ) is charged to 100 μC. Then a supercond
satela [25.4K]

Answer:

Vdc=10V

Explanation:

in a closed loop consisting of a super charged capacitor and an inductor, the super charge capacitor acts as a supply when the loop is closed, at t=0, the emf stored in the capacitor is 10V (q/c); and at that same time Vl= voltage across the inductor or loop too would be 10V,

if the loop remains closed for  a longer period, the inductor would absorb energy from the capacitor till it dissipates all charges with itself.

8 0
3 years ago
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