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Naya [18.7K]
3 years ago
9

With two reapers operating, a field can be harvested in 1 h. If only the newer reaper is used, the crop can be harvested in 1.2

h. How long would it take to harvest the field using only the older reaper?
Mathematics
1 answer:
kolezko [41]3 years ago
5 0

<u>Answer:</u>

The older repear will harvest in 6 hrs

<u>Explanation:</u>

Given a field can be harvested in 1 hr with 2 reapers

Consider the total field to be 1

Let x be the time of older’s reaper

The field can be harvested in 1.2 hr with newer reaper alone

Older’s time of harvesting = \frac{1}{x} per hour

Newer’s time of harvesting = \frac{1}{1.2}per hour

Total (Older+Newer) = 1 = {\frac{1}{x}+\frac{1}{1.2}}

 \frac{1}{x}+\frac{1}{1.2}=1

 \frac{1.2+x}{1.2 x}=1

1.2 + x = 1.2x

1.2 = 0.2x

x = 6

Therefore, older repear will harvest in 6 hrs

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Answer:

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Step-by-step explanation:

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8 0
2 years ago
Ten years ago 53% of American families owned stocks or stock funds. Sample data collected by the Investment Company Institute in
Alborosie

Answer:

a) Null hypothesis:p\geq 0.53  

Alternative hypothesis:p < 0.53  

b) z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429  

p_v =P(Z

c) So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .  

Step-by-step explanation:

Data given and notation

n=300 represent the random sample taken

\hat p=0.46 estimated proportion of American families owning stocks or stock funds

p_o=0.53 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

Part a

We need to conduct a hypothesis in order to test the claim that proportion is less than 0.53 or 53%.:  

Null hypothesis:p\geq 0.53  

Alternative hypothesis:p < 0.53  

Part b

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z

Part c  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .  

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2 years ago
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Serga [27]

Answer:

Step-by-step explanation:

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4x+60>_120

-60. -60

4x>_60

— —

4 4

X>_12

3 0
3 years ago
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