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jok3333 [9.3K]
3 years ago
12

In the reaction 4Al+_O2→2Al2O3 , what coefficient should be placed in front of the o2 to balance the reaction?​

Chemistry
2 answers:
deff fn [24]3 years ago
7 0

Answer:

yeep the answer is 3... i just took the k12 test rn

DIA [1.3K]3 years ago
4 0

Answer:

3

Explanation:

took the test

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HBr can be added to alkenes in either the absence or presence of peroxides (producing either the Markovnikov or the anti-Markovn
Dmitrij [34]

Answer:

1) 2-bromobutane

2) 1-bromobutane

Explanation:

In the HBr reaction, we will have a <u>markovniknov reaction</u> due to the <u>carbocation formation</u>. The Br- then would be added in the <u>most substituted</u> carbon of the double bond.

In the HBr/peroxide reaction we have the opposite case: an <u>anti-markovnikov reaction</u>. Therefore the Br- would be added in the <u>least substitued</u> carbon of the double bond.

3 0
3 years ago
Attempt 3 During an experiment, a student adds 2.90 g CaO 2.90 g CaO to 400.0 mL 400.0 mL of 1.500 M HCl 1.500 M HCl . The stude
kondor19780726 [428]

Answer:

Explanation:

Equation of the reaction:

CaO(s) + 2H+(aq) -----> Ca2+(aq) + H2O(g)

The ∆Hrxn would be for one mole of CaO reacted or 2 moles of H+, whichever is the limiting reactant.

Number of moles = mass ÷ molar mass

Molar mass of CaO = 40 + 16

= 56 g/mol

moles of CaO = 2.90/56

= 0.0518 mol

Number of moles = concentration × volume

moles of HCl = 400 × 10^-3 × 1.500 = 0.6 moles

Moles of HCl = moles of H+

From the equation, 1 mole of CaO reacted with 2 moles of H+ to give 1 mole of water.

To find the limiting reagent,

0.6 mole of H+/2 moles of H+ × 1 mole of CaO

= 0.3 moles of CaO(> 0.0518 moles)

So, CaO is limiting reactant.

∆H = m × Cp × ∆T

m = density × volume

= 400 × 1

= 400 g

Cp = 4.184 J/g-ºC

∆T = +6 ºC

∆H = 400 × 4.184 × 6

= 10041.6 J

Since the reaction is exothermic,

∆Hrxn = -∆H/mol(CaO)

= -10041.6/0.0518

= -193853 J

= -193.9 kJ/mol.

3 0
3 years ago
What makes up a film badge?
Inessa [10]

Film badges is a personal dosimeter used for monitoring cumulative radiation dose due to ionizing radiation.

A panel or layers of photographic film covered with black paper and exposed to air ,salt,and other chemicals on clear acetate

8 0
3 years ago
Read 2 more answers
Which statement is best supported by the diagram?
wlad13 [49]

Answer:

The answer is A.

Explanation:

when the ball gets to R and S then that's when gravity starts to take over instead of kinetic energy so therefore its potential energy

7 0
3 years ago
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The formation constant for the following reaction is Kf = 5.6 108 at 25°C. Ni2+(aq) + 6 NH3(aq) Ni(NH3)62+(aq) (a) Determine G0
marusya05 [52]

Answer:

a. ΔG⁰ = -49.9 kJ/mol

b. The reaction proceeds towards right direction

c. ΔG = 49.5 kJ/mol

d. The reaction proceeds towards left direction

Explanation:

a. It is possible to obtain ΔG⁰ from K reaction using:

ΔG⁰ = -RT ln K

<em>Where R is gas constant 8.314 J/molK, T is absolute temperature (273.15 +25 = 298.15K)</em>

Replacing:

ΔG⁰ = -8.314 J/molK 298.15K ln 5.6x10⁸

<em>ΔG⁰ = -49.9 kJ/mol</em>

b. Reaction quotient Q, defines concentrations of substances involved in an equilibrium, when Q = Kf, the reaction is in equilibrium, when Q < Kf the reaction moves towards right direction and vice versa.

At standard-state concentrations, Q = 1, as:

Q < Kf,  <em>the reaction proceeds towards right direction</em>

<em></em>

c. ΔG = ΔG⁰ + RT ln Q

Q = [Ni(NH₃)₆²⁺] / [NH₃]⁶[Ni²⁺]

Q = 0.017M / 0.0015M⁶×0.0058M

Q = 2.6x10¹⁷

ΔG = -49.9 kJ/mol + 8.314x10⁻³ kJ/molK 298.15K ln 2.6x10¹⁷

<em>ΔG = 49.5 kJ/mol</em>

<em></em>

d. As Q > Kf, <em>the reaction proceeds towards left direction</em>

7 0
3 years ago
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