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jok3333 [9.3K]
3 years ago
12

In the reaction 4Al+_O2→2Al2O3 , what coefficient should be placed in front of the o2 to balance the reaction?​

Chemistry
2 answers:
deff fn [24]3 years ago
7 0

Answer:

yeep the answer is 3... i just took the k12 test rn

DIA [1.3K]3 years ago
4 0

Answer:

3

Explanation:

took the test

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What have scientists been able to use to create the Geologic Time Scale?
dem82 [27]
The half-life of the carbon-14 isotope is used in dating fossils in a process called radiocarbon dating.

hope this is adequate. 
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2 years ago
What is the [OH-] in a solution<br> with a pol of 7.86?
yulyashka [42]

Answer:

pH of 7.86, then the [OH-] is equal to 10^(14-7.86) = 10^6.14 M

Explanation:

3 0
3 years ago
The empirical formula of styrene is ch; its molar mass is 104.1 g/mol. what is the molecular formula of styrene? select one:
Nuetrik [128]
The empirical formula is a formula of a compound showing the proportion of each element involved in the compounds but it does not represent the total number of atoms in the compound. It is the lowest number of ratio between the elements in the compound. In order, to determine the actual number of the atoms or the molecular formula of the compounds, we make use of the molar mass of the compound. 

<span>To determine the molecular formula, we multiply a value to the empirical formula. Then, calculate the molar mass and see whether it is equal to the one given (104.1 g/ mol). From the choices, the only valid options are b, d and e.
</span>                  molar mass
1     CH          13.02
8   C8H8      104.16
6   C6H6      78.12

Therefore the correct answer is option B.
6 0
3 years ago
Read 2 more answers
Write a chemical equation for the reaction that occurs in the following cell: Cu|Cu2+(aq)||Ag+(aq)|Ag Express your answer as a b
Alinara [238K]

Answer:

Explanation:

The cell reaction properly written is shown below:

              Cu|Cu²⁺_{aq} || Ag⁺_{aq} | Ag

From this cell reaction, to get the net ionic equation, we have to split the reaction into their proper oxidation and reduction halves. This way, we can know that is happening at the electrodes and derive the overall net equation.

  Oxidation half:

                  Cu_{s}  ⇄ Cu²⁺_{aq} + 2e⁻

At the anode, oxidation occurs.

  Reduction half:

                  Ag⁺_{aq} + 2e⁻ ⇄ Ag_{s}

At the cathode, reduction occurs.

To derive the overall reaction, we must balance the atoms and charges:

             Cu_{s}  ⇄ Cu²⁺_{aq} + 2e⁻

              Ag⁺_{aq} + e⁻ ⇄ Ag_{s}

  we multiply the second reaction by 2 to balance up:

         2Ag⁺_{aq} + 2e⁻ ⇄ 2Ag_{s}

The net reaction equation:

Cu_{s} + 2Ag⁺_{aq} + 2e⁻⇄ Cu²⁺_{aq} + 2e⁻ + 2Ag_{s}

We then cancel out the electrons from both sides since they appear on both the reactant and product side:

  Cu_{s} + 2Ag⁺_{aq} ⇄ Cu²⁺_{aq} + 2Ag_{s}

6 0
2 years ago
How many moles are in 20 grams of O₂ gas?
Dima020 [189]
20 g O2 x 1 mol O2/32 g O = 0.625 mol O2
4 0
2 years ago
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