Ask question

Ask question

All categories

3 years ago

15

A house wife forgot her bank'Atm pin'which is a four digit number,but luckily she remembered some hints on how to recall this 'p

in'
Here are some of the clues.
1)The 1st digit is half the 2nd.
2)The sum of the 2nd and 3rd is 10.
3)The 4th is equal to the 2nd plus 1.
4)The sum of all the digits is 23.

What is the Atm pin?

please answer the questions with steps clearly staking out.
thanks

1 answer:

Liono4ka [1.6K]3 years ago

6 0

Answer:

4829

Step-by-step explanation:

If the first digit is half of the second, that means the second is 2 times the first

So let's solve this algebraically...

The first digit could be called <em>a</em>

The second digit would have to be 2 times a (2a)

We can call the 3rd digit b

Since the sum of the second and third digit is 10, the equation would be this..

2x + b = 10, which is the same as b = 10 - 2x

The fourth digit is this equation

2x + 1

So the four digits are...

x, 2x, 10-2x, 2x+1

They are all equal to 23, which means...

x + 2x + 10-2x + 2x +1 = 23

After simplifying...

3x + 11 = 23

3x = 23 - 11

Which means...

3x = 12, x = 4

After you plug all that back into the prior equation you should get

first digit = 4 second digit = 8 third digit = 2 fourth digit = 9

Thank me later :)

(or just mark brainliest)

You might be interested in

Write the quadratic equation in general form. (x - 3)^ 2 = 0

algol [13]

The answer is: x² – 6x + 9 = 0 .
_____________________________________________________
Explanation:
________________________________________________________

Given: (x – 3)² = 0 ; write as: general form: "ax² + bx + c = 0"; a ≠ 0 .
<span>
Note: </span>(x – 3)² = (x – 3)(x – 3) = x² – 3x – 3x + 9 = x² – 6x + 9 ;
___________________________________________________
Rewrite: (x – 3)² = 0 ; →
as: x² – 6x + 9 = 0 ; which is our answer.
____________________________________________
→ x² – 6x + 9 = 0 ; is in "general form", or "standard equation format"; that is: " ax² + bx + c = 0 "; (a ≠ 0) ;
→ in which:
a = 1 (implied coefficient, since anything multiplied by "1" is that same value);
b = -6;
c = 9
_______________________________________________________

5 0

3 years ago

Read 2 more answers

Someone please explain this question PART "b) i" ONLY!!!

Gnom [1K]

<h3>Answer: (n-1)^2</h3>

This is because we have a list of perfect squares 0,1,4,9,...

We use n-1 in place of n because we're shifting things one spot to the left, since we start at 0 instead of 1.

In other words, if the answer was n^2, then the first term would be 1^2 = 1, the second term would be 2^2 = 4, and so on. But again, we started with 0^2 = 0, so that's why we need the n-1 shift.

You can confirm this is the case by plugging n = 1 into (n-1)^2 and you should find the result is 0^2 = 0. Similarly, if you tried n = 2, you should get 1^2 = 1, and so on. It appears you already wrote the answer when you wrote "Mark Scheme".

All of this only applies to sequence A.

side note: n is some positive whole number.

8 0

3 years ago

Can anyone help me with this page i can’t find the answers

Dvinal [7]

1) f(x)=2x

when x=3 then f(x) =3×2=<em><u>6</u></em>

when x=4 then f(x)=4×2=<em><u>8</u></em>

2)At y=35(no. of mangoes),x corresponds to y=60(amount)

so$<em><u>6</u></em><em><u>0</u></em><em><u>,</u></em><em><u> </u></em><em><u>amount</u></em><em><u> </u></em><em><u>he</u></em><em><u> </u></em><em><u>need</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>spend</u></em><em><u>!</u></em>

3) f(x)= x+2

for x=1, f(x)=1+2=<em><u>3</u></em>

for x=2,f(x)=2+2=<em><u>4</u></em>

✌️:)

8 0

3 years ago

Simplify 2 √3 times 3 √15<br> Also simplify 3 √5 times √5 <br> Please help

stira [4]

answer one would be 18 square root of 5

and the second would be 4 square root of 5

Step-by-step explanation:

6 0

3 years ago

How to factor 6n2 - 6n - 12

alexandr402 [8]

We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:

$6n^2-6n-12 = 6(n^2-n-2)$

We can set this equal to 0 and factor by using the quadratic formula which is:

$x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

So, let's do just that:

$6(n^2-n-2) = 0$

Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:

$\frac{1 \pm \sqrt{(-1)^2-4(1)(-2)} }{2(1)} = \frac{-1 \pm \sqrt{1-(-8)} }{2}$

$\frac{-1 \pm \sqrt{9} }{2} = {1, -2}$

So, we can write this as:

$6n^2 - 6n - 12 = 6(n-1)(n+2)$

Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!

7 0

3 years ago