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Simora [160]
3 years ago
11

Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.320 mm wide. The diffraction pattern is observed

on a screen 2.60 m away. Define the width of a bright fringe as the distance between the minima on either side.
Physics
1 answer:
DanielleElmas [232]3 years ago
8 0

Answer:

W = 10.28\ mm

Explanation:

Given,

Red light wavelength = 633 nm

width of slit = 0.320 mm

distance,d = 2.60 m

Condition of first maximum

a sin \theta_1 = m\lambda

\theta_1 =sin^{-1}(\dfrac{m\lambda}{a})

m = 1

\theta_1 =sin^{-1}(\dfrac{633\times 10^{-9}}{0.32\times 10^{-3}})

\theta_1 = 0.1133^\circ

Width of the first minima

y_1 = L tan \theta_1

y_1 = 2.60\times tan( 0.11331)

y_1 = 5.14 \ mm

Now, width of the central region

W = 2 y_1

W = 2\times 5.14

W = 10.28\ mm

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Answer:

Work done, W = 5534.53 J

Explanation:

It is given that,

Force acting on the piano, F = 6157 N

It is pushed up a distance of 2.41 m friction less plank.

Let W is the work done in sliding the piano up the plank at a slow constant rate. It is given by :

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Since, F=F\ sin\theta (in vertical direction)

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So, the work done in sliding the piano up the plank is 5534.53 J. Hence, this is the required solution.

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grandymaker [24]

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svlad2 [7]

Answer:

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Hope it helps...

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