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Brilliant_brown [7]
3 years ago
7

Find three consecutive even integers, such that

Mathematics
1 answer:
Svet_ta [14]3 years ago
8 0

Answer:

2, 4 and 6 are consecutive even integers that fit the criterion.

Step-by-step explanation:

Model the problem as an equation

let a be first integer, b be second, c be third

8a = b+c+6

Since these are consecutive even integers:

b = a + 2

c = b + 2 = a + 4

Substitute these equivalents into the equation

8a = (a+2)+(a+4)+6

Combine like terms

8a = a+2+a+4+6

8a = 2a + 12

Isolate a

6a = 12 (divide both sides by 6)

a = 2

Sub a=2 into b=a+2 and c=a+4

b=a+2 = 2+2 = 4

b=4

c=a+4 = 2+4 = 6

c=6

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Use the substitution method to solve the system of equations. Choose the correct ordered pair. x + y = 11 -x = -y - 9
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Step-by-step explanation:

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In a factory, 53 workers receive a wage of 7,576 each per month. Find the total wages received by all the workers for one financ
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Step-by-step explanation:

as you know, there are 12 months per year.

also, the word "annual" means "per year" (of again 12 months).

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8 0
3 years ago
En una hoja de papel cuyo perímetro es de 96 centímetros, se quiere imprimir un volante de manera que el área impresa sea un rec
elixir [45]

Answer:

El perímetro de la región impresa es 72 cm y su área es 288 cm².  

Step-by-step explanation:

1. Tenemos el perímetro de la hoja de papel:

P₁ = 96 cm = 2l₁ + 2a₁  (1)  

Como sabemos el margen superior, inferior, izquierdo y derecho podemos encontrar la relación entre el largo y ancho del rectángulo interno (región impresa) con el largo (l) y ancho (a) del rectángulo externo (hoja de papel):      

l_{2} = l_{1} - (m_{s} + m_{i}) = l_{1} - (3 cm + 2 cm) = l_{1} - 5 cm  (2)            

a_{2} = a_{1} - (m_{d} + m_{iz}) = a_{1} - (2 cm + 5 cm) = a_{1} - 7 cm   (3)    

El perímetro del rectángulo interno es:

P_{2} = 2l_{2} + 2a_{2}    (4)

Introduciendo la ecuación (2) y (3) en (4):

P_{2} = 2l_{2} + 2a_{2} = 2(l_{1} - 5 cm) + 2(a_{1} - 7 cm) = 2l_{1} + 2a_{1} - 10 cm - 14 cm = 96 cm - 24 cm = 72 cm  

Por lo tanto el perímetro del rectángulo interno (región impresa) es 72 cm.

 

2. Ahora para encontrar el área rectángulo interno debemos encontrar el largo y ancho del mismo, sabiendo que:

l_{2} = 2a_{2}     (5)

Introduciendo (5) en (4):

P_{2} = 2l_{2} + 2a_{2} = 2*2a_{2} + 2a_{2} = 6a_{2}

a_{2} = \frac{P_{2}}{6} = \frac{72 cm}{6} = 12 cm

l_{2} = 2a_{2} = 2*12 cm = 24 cm

Entonces el área es:

A_{2} = l_{2}*a_{2} = 12 cm*24 cm = 288 cm^{2}

Por lo tanto el área del rectágulo interno (región impresa) es 288 cm².      

Espero que te sea de utilidad!  

7 0
3 years ago
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