What is the 8th term of the following geometric sequence? 3, 15, 75, 375, …

1 answer:

3 0

$a_1=3\\a_2=3\cdot5=15\\a_3=15\cdot5=75\\a_4=75\cdot5=375\\\vdots\\\\\text{The general term of a geometric sequence}\ a_n=a_1r^{n-1}\\\\a_1-first\ term\\r-common\ ratio\\\\a_1=3,\ r=5\\\\\text{substitute}\\\\a_n=3(5^{n-1})\\\\8th\ term\to a_8\\\\\text{Substitute}\ n=8\ \text{to the equation of}\ a_n:\\\\a_8=3(5^{8-1})=3(5^7)=3(78125)=234,375\\\\Answer:\ 8th\ term=234,375$

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zavuch27 [327]

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<h3>How to find the volume of a square-based right pyramid?</h3>

Supposing that:

The length of the sides of the square base of the pyramid has = b units

The height of the considered square-based pyramid = h units,

The pyramid below has a square base.

h = 24.4 cm

b = 17.2 cm

Then, its volume is given by:

$V = \dfrac{1}{3} \times b^2 \times h \: \rm unit^3$

$V = \dfrac{1}{3} \times 17.2^2 \times 24.4 \: \rm unit^3\\\\V = 2406.16$

Therefore, the volume of the pyramid would be 2406.16 cubic cm.

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