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svetlana [45]
4 years ago
6

Use​ Green's Theorem to evaluate the line integral. Assume the curve is oriented counterclockwise. Contour integral Subscript Up

per C Superscript Baseline (7 x plus cosine StartFraction 1 Over y EndFraction )dy minus (3 y squared plus ln 3 x )dx ​, where C is the boundary of the square with vertices (1 comma 0 )comma (4 comma 0 )comma (4 comma 3 )comma and (1 comma 3 ). Contour integral Subscript Upper C Superscript Baseline (7 x plus cosine StartFraction 1 Over y EndFraction )dy minus (3 y squared plus ln 3 x )dx ​= nothing ​(Type an exact​ answer.)
Mathematics
1 answer:
Setler79 [48]4 years ago
4 0

By Green's theorem, we have

\displaystyle\int_C\left(7x+\cos\frac1y\right)\,\mathrm dy-(3y^2+\ln(3x))\,\mathrm dx

=\displaystyle\iint_{[1,4]\times[0,3]}\frac{\partial\left(7x+\cos\frac1y\right)}{\partial x}-\frac{\partial(-(3y^2+\ln(3x))}{\partial y}\,\mathrm dx\,\mathrm dy

=\displaystyle\int_0^3\int_1^47+6y\,\mathrm dx\,\mathrm dy=\boxed{144}

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Step-by-step explanation:

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8 0
3 years ago
What is the equation of a circle with center (1,-4) and radius 2?
mihalych1998 [28]

Step-by-step explanation:

Centre of circle(h,k)=(1,-4)

radius of the circle(r)=2

Equation of the circle is,

(x-h)^2+(y-k)^2=r^2

(x-1)^2+(y+4)^2=2^2

x^2-2x+1+y^2+8y+16=4

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8 0
3 years ago
Which of the following polynomials corresponds to the subtraction of the multivariate polynomials 19x^3+44x^2y+17 and y^3-11xy^2
VARVARA [1.3K]
Name the two given polynomials as
f(x) = 19x³ + 44x²y + 17
g(x) = y³ - 11xy² + 2x²y - 13x³

Create the subtraction f(x) - g(x).
f(x)-g(x) = 19x³ + 44x²y + 17 - (y³ - 11xy² + 2x²y - 13x³)
             = (19 + 13)x³ + (44 - 2)x²y + 11xy² - y³ + 17
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Answer: D
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7 0
4 years ago
F – 6 = -2f + 3(f – 2) show your work please
Evgen [1.6K]

f - 6 = -2f + 3(f - 2)

f - 6 = -2f + 3f - 6

f + 2f - 3f = -6 + 6

0 = 0

Every number is solution this equation.

8 0
3 years ago
You have a rectangular garden that is 10 feet
Ahat [919]

a. If you double both sides, you'll get a rectangle with dimensions 20 feet wide and 30 feet long, therefore the area will be 20 × 30 = 600 feet².

b. The area of the old rectangle was 10 × 15 = 150 feet², so no the area is not twice as large, it is 4 times as large. This is because if the area is base × height, then doubling both of these gets you (2 × base) × (2 × height) = 4 × (base × height).

I hope this helps!

6 0
3 years ago
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