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svetlana [45]
3 years ago
6

Use​ Green's Theorem to evaluate the line integral. Assume the curve is oriented counterclockwise. Contour integral Subscript Up

per C Superscript Baseline (7 x plus cosine StartFraction 1 Over y EndFraction )dy minus (3 y squared plus ln 3 x )dx ​, where C is the boundary of the square with vertices (1 comma 0 )comma (4 comma 0 )comma (4 comma 3 )comma and (1 comma 3 ). Contour integral Subscript Upper C Superscript Baseline (7 x plus cosine StartFraction 1 Over y EndFraction )dy minus (3 y squared plus ln 3 x )dx ​= nothing ​(Type an exact​ answer.)
Mathematics
1 answer:
Setler79 [48]3 years ago
4 0

By Green's theorem, we have

\displaystyle\int_C\left(7x+\cos\frac1y\right)\,\mathrm dy-(3y^2+\ln(3x))\,\mathrm dx

=\displaystyle\iint_{[1,4]\times[0,3]}\frac{\partial\left(7x+\cos\frac1y\right)}{\partial x}-\frac{\partial(-(3y^2+\ln(3x))}{\partial y}\,\mathrm dx\,\mathrm dy

=\displaystyle\int_0^3\int_1^47+6y\,\mathrm dx\,\mathrm dy=\boxed{144}

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Five-sixths of a number is 45.<br> Find the number.
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Answer: The number is 54!!!

Hope it helps!!!



Step-by-step explanation:

Let's call the number x.

So, 5/6 (of or multiplication) = 45

5x = 45* 6

x = 270/5

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3 years ago
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Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

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The three populations has the following proportions:

p₁ = 0.10

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p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

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Answer:

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Step-by-step explanation:

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