Answer:
The answer to the question is;
The probability that the resulting sample mean of nicotine content will be less than 0.89 is 0.1587 or 15.87 %.
Step-by-step explanation:
The mean of the distribution = 0.9 mg
The standard deviation of the sample = 0.1 mg
The size of the sample = 100
The mean of he sample = 0.89
The z score for sample mean is given by
where
X = Mean of the sample
μ = Mean of the population
σ = Standard deviation of the population
Therefore Z =
= -1
From the standard probabilities table we have the probability for a z value of -1.0 = 0.1587
Therefore the probability that the resulting sample mean will be less than 0.89 = 0.1587 That is the probability that the mean is will be less than 0.89 is 15.87 % probability.
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Answer with explanation:
Let p be the proportion of adults have heard of the new electronic reader.
Given claim : The accompanying technology display results from a test of the claim that 38% of adults have heard of the new electronic reader.
i.e.
Then , the set of hypothesis will be :-

Since, the alternative hypothesis is two tailed , so the test is two-tailed test.
Also, it is given that the sample size : 
Number of adults showed that they have heard of a new electronic reader=522
So the sample proportion for adults have heard of the new electronic reader : 
The test statistic for proportion is given by :-
By using standard normal distribution table , the P-value for two tailed test corresponds to the obtained z-value =
For your question the answer is C.
Hope this helps:)