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ser-zykov [4K]
2 years ago
8

What element produces violet light of approximately 412 nm?

Chemistry
2 answers:
Natali [406]2 years ago
8 0
a. Hydrogen

Hydrogen has a line at 410 nm.
Mercury has a line at 405 nm.
Sodium and neon have no lines near 412 nm.
irinina [24]2 years ago
4 0

Answer:

a. Hydrogen

Explanation:

Emission spectrum of hydrogen produces four main visible wavelengths out of which one is violet light at 412 nm.

Mercury has visible prominent lines of blue, green and yellow-orange.

Sodium has two prominent very close yellow wavelengths in its emission spectrum.

Neon spectra also consists of green to red lines but not violet light.

Thus, correct option is a.

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The atom in a sample of an element must contain nuclei with the same number of?
slava [35]
Hey there! 

Answer: Protons 

The atom in a sample of an element must contain nuclei with the same number of protons. If the protons change in number, then the element will modify as well. 

Thank you!
7 0
3 years ago
Rank the following elements in order of decreasing atomic radius (1 is biggest, 5 is smallest)
AlexFokin [52]

There are various kind of elements that are present in periodic table. Some elements are harmful, some are radioactive, some are noble gases. The atomic radius in decreasing order is Bi>Sb>As>N>O.

<h3>What is periodic table?</h3>

Periodic table is a table in which we find elements with properties like metals, non metals, metalloids and radioactive element arranges in increasing atomic number.

Along the period, the size of elements decreases. Down the group the size of elements increases. The atomic radius in decreasing order is Bi>Sb>As>N>O.

Therefore, atomic radius in decreasing order is Bi>Sb>As>N>O.

Learn more about periodic table, here:

brainly.com/question/11155928

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3 0
1 year ago
Realiza los cálculos para determinar la cantidad de KOH 90%, que se necesita para preparar 100 ml de solución 1N.
attashe74 [19]

Answer:

6.23 KOH 90% son necesarios

Explanation:

Una solución 1N de KOH requiere 1equivalente (En KOH, 1eq = 1mol) por cada litro de solución.

Para responder esta pregunta se requiere hallar los equivalentes = Moles de KOH para preparar 100mL = 0.100L de una solución 1N. Haciendo uso de la masa molar de KOH y del porcentaje de pureza del KOH se pueden calcular los gramos requeridos para preparar la solución así:

<em>Equivalentes KOH:</em>

0.100L * (1eq / L) = 0.100eq = 0.100moles

<em>Gramos KOH -Masa molar: 56.1056g/mol-:</em>

0.100moles * (56.1056g/mol) = 5.61 KOH se requieren

<em>KOH 90%:</em>

5.61g KOH * (100g KOH 90% / 90g KOH) =

<h3>6.23 KOH 90% son necesarios</h3>
8 0
2 years ago
Please help, need asap, just tell me where they go​
Lostsunrise [7]

Answer:

1 to 2 3 to 6

Explanation:

5 0
2 years ago
Anyone have a good tip, or app to help me with nomenclature???
ExtremeBDS [4]
Nomenclature of what?
3 0
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