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3 years ago

Can rotation and revolution occur at the same time? Explain.

Chemistry

1 answer:

Ipatiy [6.2K]3 years ago

5 0

Answer:

yes

Explanation:

Revolution is the movement of an object around another object. So, Earth revolves around the Sun, and the Moon revolves around Earth. At the same time, Earth and the Moon are also rotating. Earth's rate of revolution is about 365 days (one year), and its rate of rotation is about 24 hours (one day).

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What is the name of the covalent compound CCl4?

zubka84 [21]

Think, first, about the type of molecule or formula unit you have (covalent or ionic). In this case, it is a covalent molecule. You start with the carbon. You could say monocarbon, but if it is just said to be carbon it is assumed to be one. Then you take the prefix for 4 and tack it on to the beginning of the chlorine. For this, the name is carbon tetrachloride.

4 0

2 years ago

Two identical pots, one black and one silver, containing exactly the same amounts of water, are heated to the same temperature.

I am Lyosha [343]

The most probable answer is: (a) The black pot emits heat at a faster rate than the silver pot. It means the black pot conducts heat at a higher rate than the silver pot, that's why it cooled off faster. It also means that the silver pot retains heat better and is more of an insulator.

7 0

2 years ago

Read 2 more answers

Another chemistry question i’m not good at this at all:( has me stressed

adoni [48]

Answer:

Average atomic mass = 15.86 amu.

Explanation:

Given data:

Number of atoms of Z-16.000 amu = 205

Number of atoms of Z-14.000 amu = 15

Average atomic mass = ?

Solution:

Total number of atoms = 205 + 15 = 220

Percentage of Z-16.000 = 205/220 ×100 = 93.18%

Percentage of Z-14.000 = 15/220 ×100 = 6.82 %

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100

Average atomic mass = (93.18×16.000)+(6.82×14.000) /100

Average atomic mass = 1490.88 + 95.48 / 100

Average atomic mass = 1586.36 / 100

Average atomic mass = 15.86 amu.

5 0

3 years ago

How many dm³ of hydrogen,measured at s.t.p.,would be needed to reduce 47.7g of copper(II) oxide to copper?

GaryK [48]

Answer:

Option D. 13.44

Explanation:

We'll begin by calculating the number of mole in 47.7g of copper(II) oxide, CuO.

This can be obtained as follow:

Mass of CuO = 47.7 g

Molar mass of CuO = 63.5 + 16 = 79.5 g/mol

Mole of CuO =.?

Mole = mass /Molar mass

Mole of CuO = 47.7/79.5

Mole of CuO = 0.6 mole

Next, we shall write the balanced equation for the reaction. This is given below:

CuO + H2 —> Cu + H2O

From the balanced equation above,

1 mole of CuO reacted with 1 mole of H2 to produce 1 mole of Cu and 1 mole of H2O.

Next, we shall determine the number of mole of H2 needed to react completely with 0.6 mole of CuO.

This can be obtained as follow:

From the balanced equation above,

1 mole of CuO reacted with 1 mole of H2.

Therefore, 0.6 mole of CuO will also react with 0.6 mole of H2.

Finally, we shall determine the volume occupied by 0.6 mole of H2 at STP.

This can be obtained as follow:

1 mole of H2 occupied 22.4 dm³ at STP.

Therefore, 0.6 mole of H2 will occupy = 0.6 × 22.4 = 13.44 dm³.

Therefore, 13.44 dm³ of H2 is needed for the reaction.

4 0

2 years ago

Occupational Safety and Health Administration has set the limit on the maximum percentage of carbon dioxide (CO2) in air a worke

Lyrx [107]

Answer:

The minimum rate of fresh air in the room is 176 moles/min

Explanation:

High exposure of CO₂ has health effects as headaches, increased heart rate, elevated blood pressure, coma, asphyxia, convulsions, etc.

0,500 mole% of CO₂ in air means 0,500 moles of CO₂ per 100 moles of air

As the rate of sublimation of CO₂ is 0,880, the minimum rate of fresh air in the room must be:

$\frac{0,500 moles CO_{2}}{100 moles Air} = \frac{0,880 moles CO_{2}/min}{X}$

X = 176 moles of Air/min

I hope it helps!

4 0

2 years ago