The third option, 2,2,1,2
Answer:
not affected?
Explanation:
pretty sure M / concentration isn't affected, only volume.
Answer:
2Al+1.5O2→Al2O3
Thus, 2 mol of Al combine with 1.5 mol of oxygen to form 1 mol of Al2O3.
2 mol of Al corresponds to 2×27=54 g.
Thus, the weight of Al used in the reaction is 54 g.
Anything that has mass and occupies space.
