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Anuta_ua [19.1K]
2 years ago
13

Practice Problems Exercise 8.6 Classify each of the following reactions in as many ways as possible.4N H3 (g) 5 O2 (g) n 4NO(g)

6 H2 O(g) b. S8 (s) 8 O2 (g) n 8S O2 (g) c. 2Al(s) 3C l 2 (g) n 2AlC l 3 (s) d. 2AlN(s) n 2Al(s) N2 (g) e. BaC l 2 (aq) N a2 S O4 (aq) n BaS O4 (s) 2NaCl(aq) f. 2Cs(s) B r2 (l) n 2CsBr(s) g. KOH(aq) HCl(aq) n H2 O(l) KCl(aq) h. 2 C2 H 2 (g) 5 O2 (g) n 4C O2 (g) 2 H2 O(l)
Chemistry
1 answer:
nikklg [1K]2 years ago
6 0

Explanation :

(a) 4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)

This reaction is combustion reaction in which an oxygen react with a molecule to give its corresponding oxides ans water molecule.

(b) S_8(s)+8O_2(g)\rightarrow 8SO_2(g)

This reaction is a redox reaction or oxidation-reduction reaction in which sulfur get oxidized and oxygen get reduced.

(c) 2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3(s)

This reaction is a combination reaction in which the two reactants molecule combine to form a large molecule or product.

(d) 2AlN\rightarrow 2Al(s)+N_2(g)

This reaction is a decomposition reaction in which a large molecule or reactant decomposes to give two or more molecule or products.

(e) BaCl_2(aq)+Na_2SO_4(aq)\rightarrow BaSO_4(s)+2NaCl(aq)

This reaction is a double displacement reaction in which the cation of two reactants molecule exchange their places to give two different products.

(f) 2Cs(s)+Br_2(l)\rightarrow 2CsBr(s)

This reaction is a combination reaction in which the two reactants combine to form a large molecule or product.

(g) KOH(aq)+HCl(aq)\rightarrow H_2O(l)+KCl(aq)

This reaction is a double displacement reaction in which the cation of two reactants molecule exchange their places to give two different products.

(h) 2C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(l)

This reaction is combustion reaction in which a hydrocarbon react with an oxygen to give carbon dioxide and water as a products.

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Consider the reaction at 25 °C. H2O(l) ↔ H2O(g) ΔG° = 8.6 kJ/mol Calculate the pressure of water at 25 °C (Hint: Get K eq)
tangare [24]

Answer:

\boxed{\text{23.4 mmHg}}

Explanation:

H₂O(ℓ) ⟶ H₂O(g)

K_{\text{p}} = p_{\text{H2O}}

\text{The relationship between $\Delta G^{\circ}$ and $K_{\text{ p}}$ is}\\\Delta G^{\circ} = -RT \ln K_{\text{p}}

Data:  

T = 25 °C

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Calculations:

T = (25 + 273.15) K = 298.15 K

\begin{array}{rcl}8600 & = & -8.314 \times 298.15 \ln K \\8600 & = & -2478.8 \ln K\\-3.47 & = & \ln K\\K&=&e^{-3.47}\\& = & 0.0311\end{array}

Standard pressure is 1 bar.

p_{\text{H2O}} = \text{0.0311 bar} \times \dfrac{\text{750.1 mmHg}}{\text{1 bar}} = \textbf{23.4 mmHg}\\\\\text{The vapour pressure of water at $25 ^{\circ}\text{C}$ is $\boxed{\textbf{23.4 mmHg}}$}

4 0
2 years ago
A gas that has a volume of 28 liters, a temperature of 45 °C, and an unknown pressure has its volume increased
allochka39001 [22]

Answer:

2.5 atm

Explanation:

V1 = 28L

T1 = 45°C = (45 + 273.15)K = 318.15K

V2 = 34L

T2 = 35°C = (35 + 273.15)K = 308.15k

P2 = 2.0atm

P1 = ?

From general gas equation,

(P1 × V1) / T1 = (P2 × V2) / T2

P2 × V2 × T1 = P1 × V1 × T2

P1 = (P2 × V2 × T1) / (V1 × T2)

P1 = (2.0 × 34 × 318.15) / (28 × 308.15)

P1 = 21634.5 / 8628.2

P1 = 2.5 atm

The initial pressure of the gas is 2.5atm

5 0
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