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pashok25 [27]
3 years ago
6

Because air contracts as it cools, the air pressure inside a freezer is typically lower than on the outside. Why do ice cubes in

side a freezer tend to shrink over time?
A. The ice dissolves oxygen from the air, forming a denser crystalline matrix.

B. The ice reacts chemically with carbon dioxide in the air, forming gaseous carbon compounds.

C. The ice melts, and then the liquid freezes as ice crystals on the bottom of the freezer.

D. The ice sublimes, and then the water vapor deposits as ice crystals on the sides of the freezer.
Physics
1 answer:
CaHeK987 [17]3 years ago
8 0
The answer is definitely D
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The  induced current is I  =  6.25*10^{-4} \  A

Explanation:

From the question we are told that  

    The number of turns is  N  =  1

     The  cross-sectional area is  A  =  8.20 cm^2  =  8.20 * 10^{-4} \ m^2

    The  initial magnetic field is  B_i  =  0.500 \ T

     The  magnetic field at time =  1.02 s  is  B_t =  2.60 \ T

     The  resistance is  R  = 2.70\  \Omega

The  induced emf is mathematically represented as

       \epsilon  = - N  *   \frac{ d\phi }{dt}

The  negative sign tells us that the induced emf is moving opposite to the change in magnetic flux

      Here  d\phi is the change in magnetic flux which is mathematically represented as

        d \phi  =  dB  *  A

Where  dB  is the change in magnetic field which is mathematically represented as

        dB  =  B_t  - B_i

substituting values

        dB  =   2.60 -  0.500

        dB  =   2.1 \ T

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      d \phi  =  2.1 * 8.20 *10^{-4}

     d \phi  = 1.722*10^{-3} \ weber

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The  induced current i mathematically represented as

      I  =  \frac{\epsilon}{ R }

  substituting values

       I  =  \frac{1.69*10^{-3}}{ 2.70 }

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