3 years ago

A lightbulb consumed 1100J in 30 minutes. Find Power, resistance, and calculate energy in kWh

Physics

1 answer:

lisov135 [29]3 years ago

5 0

Explanation:

30 minutes is 1800 seconds.

Power = energy / time

P = 1100 J / 1800 s

P = 0.611 W

Converting the energy from J to kWh:

1100 J × (1 Ws / 1 J) × (1 kW / 1000 W) × (1 h / 3600 s) = 3.06×10⁻⁴ kWh

To find resistance, you need to be given either the voltage or the current.

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