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Westkost [7]
4 years ago
15

The probability that a certain kind of component will survive a shock test is 3/4. Find the probability that exactly 2 of the ne

xt 4 components tested survive test, assuming tests are independent.
Mathematics
1 answer:
Marina86 [1]4 years ago
3 0

Answer:

Therefore the required probability is =\frac{27}{128}

Step-by-step explanation:

The probability of success is \frac{3}{4}

The number of trial = 4

X= the items survive out of 4

P(x=r)=^nC_rq^{n-r}p^r        p =the probability of success and q = the probability failure.

p=\frac{3}{4}     and q=(1-\frac{3}{4})=\frac{1}{4}

\therefore P(X=2)=^4C_2(\frac{1}{4} )^2(\frac{3}{4} )^2

                  =\frac{4!}{2!2!} (\frac{1}{16} )(\frac{9}{16} )

                  =\frac{27}{128}

Therefore the required probability is =\frac{27}{128}

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