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2 years ago

Whoever helps me will get a $50 i tunes gift card.

Mathematics

2 answers:

Andru [333]2 years ago

7 0

The second one is (2,1)

serg [7]2 years ago

3 0

Answer:

Step-by-step explanation:

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Find the standard deviation of the sample ($23.14, $20.12, $56.21, $34.56, $43.74)

Shkiper50 [21]

Answer:

S.D=61.824137824783

Step-by-step explanation:

6 0

2 years ago

In a triangle, two angles have measures of 45 degrees and 85 degrees. What is the measure of the third angle in this triangle?

Blizzard [7]

Answer:

50 degrees

Step-by-step explanation:

All three angles in a triangle add up to 180 degrees. If you know the measure of two angles, add them together and subtract the sum from 180.

45+85=130. Then, subtract 130 from the total, or 180. 180-130=50. The measure of the third angle of the triangle is 50 degrees.

5 0

2 years ago

Help pls im taking a test and I need help on this the answer choices are

siniylev [52]

Answer:

b. K,M,J,L

Step-by-step explanation:

From weakest to strongest values:

-0.78, -0.15, 0.35, 0., 67

Weakest to strongest data sets:

K, M, J, L

4 0

2 years ago

Please help me answer this question

ratelena [41]

By the definition of the hyperbolic function tanh x, we have proven that $\frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}$

<h3>Hyperbolic functions & Proof of identities </h3>

By definition

$tanh \ x=\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}}$

Then,

$\frac{1-tanh \ x}{1 + tanh \ x}=\frac{1-\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }{1+ \frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }$

$=1-\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} \div (1+ \frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} })$

$=\frac{e^{x} +e^{-x}-(e^{x} -e^{-x})}{e^{x} +e^{-x}} \div (\frac{e^{x} +e^{-x}+e^{x} -e^{-x}}{e^{x} +e^{-x}} })$

$=\frac{e^{x} +e^{-x}-e^{x} +e^{-x}}{e^{x} +e^{-x}} \div \frac{e^{x} +e^{-x}+e^{x} -e^{-x}}{e^{x} +e^{-x}} }$

$=\frac{e^{-x}+e^{-x}}{e^{x} +e^{-x}} \div \frac{e^{x} +e^{x} }{e^{x} +e^{-x}} }$

$=\frac{2e^{-x}}{e^{x} +e^{-x}} \div \frac{2e^{x} }{e^{x} +e^{-x}} }$

$=\frac{2e^{-x}}{e^{x} +e^{-x}} \times \frac{e^{x} +e^{-x}}{2e^{x}}$

$=\frac{2e^{-x}}{1} \times \frac{1}{2e^{x}}$

$=\frac{2e^{-x}}{2e^{x}}$

$=\frac{e^{-x}}{e^{x}}$
$=e^{-x} \times \frac{1}{e^{x}}$

$= e^{-x} \times e^{-x}$

$= e^{-x+-x}$

$= e^{-x-x}$

$= e^{-2x}$

Hence, we have proven that $\frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}$

Learn more on Proof of Identities here: brainly.com/question/2561079

#SPJ1

6 0

1 year ago

HELP Solve for x and PS

ANTONII [103]

Answer:

PS = 84.5 , x = 43.75

Step-by-step explanation:

Since RQ is congruent to PS, PS is 2x - 3

SR: 4x + 1

Extra at the bottom: 4

4x + 1 + 4 = 180

4x + 5 = 180

- 5 - 5

4x = 175

/4 /4

x = 43.75

Plug in for PS

2 (43.75) - 3

87.5 - 3

84.5

I hope this helps!

4 0

2 years ago