Answer: yes
Step-by-step explanation:
Since it is given that Boris takes x minutes to run 5 miles it means that Boris' speed will be given as: 
.
Now, if Dylan runs slower than Boris and takes 12 more minutes to complete the 5 miles run, then that would mean that Dylan takes (x+12) minutes to complete the same run.
In this case we can see the Dylan's speed will be 
.
Thus, the denominator represents the time Dylan takes to run 5 miles if he takes 12 minutes more than Boris.
Therefore, out of the given options, the second option is the correct option.
109x is the expression that could be used to determine the total number of cupcakes made given that a parent made x cupcakes for each of the 109 students in the fourth grade. This can be obtained by forming the algebraic expression for the given conditions.
<h3>Find the required expression:</h3>
- Algebraic expression is made up of numbers, operations and variables.
- Algebraic expression is true for all values of x.
- For example, 2x, 5x + 9 etc.
Given that,
A parent made x cupcakes for each of the 109 students in the fourth grade.
The total number of students in the class = 109
The number of cupcakes one student gets = 1 × x = x
⇒ The number of cupcakes 109 student gets = 109 × x = 109x
Hence 109x is the expression that could be used to determine the total number of cupcakes made given that a parent made x cupcakes for each of the 109 students in the fourth grade.
Learn more about algebraic expression here:
brainly.com/question/953809
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Step-by-step explanation:
(a)
Using the definition given from the problem
![f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\](https://tex.z-dn.net/?f=f%28A%29%20%3D%20%5C%7Bx%5E2%20%20%5C%2C%20%3A%20%5C%2C%20x%20%5Cin%20%5B0%2C2%5D%5C%7D%20%3D%20%5B0%2C4%5D%5C%5Cf%28B%29%20%3D%20%5C%7Bx%5E2%20%20%5C%2C%20%3A%20%5C%2C%20x%20%5Cin%20%5B1%2C4%5D%5C%7D%20%3D%20%5B1%2C16%5D%5C%5Cf%28A%29%20%5Ccap%20f%28B%29%20%3D%20%5B1%2C4%5D%20%20%3D%20f%28A%20%5Ccap%20B%29%5C%5C)
Therefore it is true for intersection. Now for union, we have that
![A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]](https://tex.z-dn.net/?f=A%20%5Ccup%20B%20%3D%20%5B0%2C4%5D%5C%5Cf%28A%5Ccup%20B%20%29%20%3D%20%5B0%2C16%5D%5C%5Cf%28A%29%20%3D%20%5B0%2C4%5D%5C%5Cf%28B%29%3D%20%5B1%2C16%5D%5C%5Cf%28A%29%20%5Ccup%20f%28B%29%20%3D%20%5B0%2C16%5D)
Therefore, for this case, it would be true that 
.
(b)
1 is not a set.
(c)
To begin with
Therefore
Now, given an element of 
it will belong to both sets, therefore it also belongs to 
, and you would have that
, therefore 
.
(d)
To begin with 
, therefore
Literally just replace the nine and four with ANY other numbers.
