V=πr²h
1000=πr²(8)
r²=39.79
r=6.3
Hope this Helps! :D
Let's assume m represent the mileage of the car.
Given that, Primo car rental agency charges $33 per day plus $0.20 per mile.
So, the total charge for this agency = 33 + 0.20m.
Similarly total charge of the ultimo car = 17 + 0.85m.
Now we need to find the daily mileage for which the ultimo charge is four times the primo charge . So, we can set up an equation as following:
17 + 0.85m = 4 *( 33 + 0.20m )
17 + 0.85m = 132 + 0.80m By distribution property.
17 + 0.85m -0.80m = 132 + 0.80m -0.80m Subtract 0.80m from each sides.
17 + 0.05m = 132
17 + 0.05m - 17 = 132 - 17 Subtract 17 from each sides.
0.05m = 115
Divide each by 0.05.
So, m = 2300
Hence, the daily mileage is 2300 miles.
Hope this helps you!
Answer:
Step-by-step explanation:
Given equation to us is ,
So , a equation is said to be a quadratic equation if the highest degree of the variable is 2 . On simplifying the Equation ,

Taking x as LCM ,

Transposing x to RHS .

Putting all terms in LHS

Since here the highest degree of the variable is 3 not 2 . So its a cubic equation and not a quadratic equation .
<h3>
<u>Hence</u><u> </u><u>the </u><u>given </u><u>equation </u><u>is</u><u> </u><u>not</u><u> </u><u>a</u><u> </u><u>quad</u><u>ratic</u><u> equation</u><u> </u><u>.</u></h3>
Answer:
1/4
Step-by-step explanation:
The answer is 1/4 because their is a total number of 4 outcomes (denominator) and there in only 1 chance (numerator) that you will not get tails.
Answer:
4.2 units
Step-by-step explanation:
Assuming 1 grid box = 1 units, the coordinates of the two points are (-1, -1) and (2, 2).
Apply distance formula
to find the distance between (-1, -1) and (2, 2).
Let,


Plug in the values




(to the nearest tenth)