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3 years ago

$1.80 is % of $3.00; $3.00 is % of $1.80 fill in the blanks

Mathematics

1 answer:

frutty [35]3 years ago

8 0

Answer:

60% and 500/3 % respectively

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Please help as soon as possible

Inessa [10]

Answer:

tan=Opposite/Adjacent so 3/4 is the answer

Step-by-step explanation:

3 is opposite of A and 4 is Adjacent of A

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3 years ago

Read 2 more answers

Write the number 3.7 as a mixed number let x

puteri [66]

3.7/1 = 3.7

multiply it through to make it a whole number.
x 10

37
_
10

then see how mant times 10 goes into it.
3 times. so 3 is your whole number. 7/10 remains.
that is your fraction.

4 0

3 years ago

Callan is buying a square shaped platter with an area of 169 square inches what is the correct step he should take if he wants t

bagirrra123 [75]

a = length of one side.

Area of a square = a^2

in our problem,

Area = 169 square inches

a = ?

Plug our numbers into the area formula mentioned above.

169 in^2 = a^2.

Take the square root of each side to find the side length of the square shaped platter.

13 = a

4 0

3 years ago

Does the equation y=-1/3x1/3 form a straight line

weqwewe [10]

Yes because it is a linear equation

7 0

3 years ago

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago

$1.80 is ____ % of $3.00; $3.00 is ____ % of $1.80 fill in the blanks

$1.80 is % of $3.00; $3.00 is % of $1.80 fill in the blanks