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Viefleur [7K]
3 years ago
8

Kim rolls a dice and flips a coin. b) work out the probability that she gets an even number and a tail

Mathematics
2 answers:
balandron [24]3 years ago
4 0

Answer with Step-by-step explanation:

Kim rolls a dice and flips a coin.

P(any event)=number of favorable outcomes/total outcomes

A: gets an even number on rolling a die={2,4,6}

P(A)=P(getting even number)

      =3/6

     = 1/2

B: getting tail on flipping a coin

P(B)=P(getting tail)

      =1/2

Since, both events are independent

Hence, P(A∩B)=P(A)×P(B)

i.e. P(getting an even number and getting a tail)

                      =P(getting even number)×P(getting tail)

                        =\dfrac{1}{2}\times \dfrac{1}{2}

                        = 1/4

Hence,  probability that she gets an even number and a tail is:

1/4

puteri [66]3 years ago
3 0
A)3/6=1/2
b)1/2
hope it helps if u need more explanation I will give u.
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An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
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Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

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(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

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A person is obese if they have BMI 30 or more.

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(A)

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Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

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Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

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(C)

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In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

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(D)

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The events of a person being overweight and obese are mutually exclusive.

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