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Viefleur [7K]
3 years ago
8

Kim rolls a dice and flips a coin. b) work out the probability that she gets an even number and a tail

Mathematics
2 answers:
balandron [24]3 years ago
4 0

Answer with Step-by-step explanation:

Kim rolls a dice and flips a coin.

P(any event)=number of favorable outcomes/total outcomes

A: gets an even number on rolling a die={2,4,6}

P(A)=P(getting even number)

      =3/6

     = 1/2

B: getting tail on flipping a coin

P(B)=P(getting tail)

      =1/2

Since, both events are independent

Hence, P(A∩B)=P(A)×P(B)

i.e. P(getting an even number and getting a tail)

                      =P(getting even number)×P(getting tail)

                        =\dfrac{1}{2}\times \dfrac{1}{2}

                        = 1/4

Hence,  probability that she gets an even number and a tail is:

1/4

puteri [66]3 years ago
3 0
A)3/6=1/2
b)1/2
hope it helps if u need more explanation I will give u.
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3 years ago
1) The graph of g(x) is shown below. Which statement given below is FALSE?
Mnenie [13.5K]
<h3>Answer: Choice D </h3>

=======================================================

Explanation:

Let's go through the answer choices one by one to see which are true, and which are false.

  • Choice A) This is true because as we approach x = 2 from the left hand side, the y values get closer to y = 1 from the top
  • Choice B) This is true. As we get closer to x = 4 on the left side, the blue curve is heading downward forever toward negative infinity. So this is what y is approaching when x approaches 4 from the left side.
  • Choice C) This is true also. The function is continuous at x = -3 due to no gaps or holes at this location, so that means its limit here is equal to the function value.
  • Choice D) This is false. The limit does exist and we find it by approaching x = -4 from either side, and we'll find that the y values are approaching y = -2. In contrast, the limit at x = 2 does not exist because we approach two different y values when we approach x = 2 from the left and right sides (approach x = 2 from the left and you get closer to y = 1; approach x = 2 from the right and you get closer to y = -2). So again, the limit does exist at x = -4; however, the function is not continuous here because its limiting value differs from its function value.
  • Choice E) This is true because the function curve approaches the same y value from either side of x = 6. Therefore, the limit at x = 6 exists.
7 0
3 years ago
What is the simplified form of each expression? <br><br> 1.7m^2 + 6.5 - 4n + 2.5m^2 - n
nasty-shy [4]
Group like terms
1.7m^2+2.5m^2-4n-n+6.5
4.2m^2-5n+6.5
4 0
4 years ago
The sum of the roots of 8x^2- 2x
Andrews [41]

Answer:

1/4

Step-by-step explanation:

To find the roots of the expression, factor the expression by GCF.

8x^2 - 2x\\2x(4x-1)

The roots are the factors set equal to 0 and solved for x.

2x = 0

x=0

4x-1 = 0

x = 1/4

The sum is the addition of the two roots 0 + 1/4 = 1/4

8 0
3 years ago
Simplify:<br>1/1-x^(b-a)+1/1-x^(a-b)​
Pachacha [2.7K]

Answer:

<h3>1</h3>

Step-by-step explanation:

simplify:

1/1-x^(b-a)+1/1-x^(a-b)​

\frac{1}{1-x^{b-a}} + \frac{1}{1-x^{a-b}}\\= \frac{1-x^{a-b} + 1-x^{b-a}}{(1-x^{b-a})(1-x^{a-b})}\\=  \frac{1-x^{a-b} + 1-x^{b-a}}{(1-x^{b-a}-x^{a-b}+x^{b-a+a-b})}\\= \frac{1-x^{a-b} + 1-x^{b-a}}{(1-x^{b-a}-x^{a-b}+1)}\\= \frac{2-x^{a-b}-x^{b-a}}{2-x^{b-a}-x^{a-b}}\\= 1\\ \\

Hence the required answer is 1

8 0
3 years ago
Read 2 more answers
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