Answer:
Therefore the amplitude of the resultant wave is 
Explanation:
The equation of wave:
y=A sin (kx-ωt)
For wave 1:
y₁=A sin (kx-ωt) =
sin (kx-ωt)
For wave 2:
y₂=A sin (kx-ωt+Φ) =
sin (kx-ωt+Φ)
Where A= amplitude=
The angular frequency 
,
= wave length.
t= time
T= Time period
= phase difference = 
The resultant wave will be
y = y₁ + y₂
=
sin (kx-ωt) +
sin (kx-ωt+Φ)
{sin (kx-ωt) + sin (kx-ωt+Φ)}



Therefore the amplitude of the resultant wave is



<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>
Given that ,
- Initial Velocity of car = 44km / hr.
- Final Velocity of car = 0km / hr.
- Acceleration = -5km/hr².
To Find :
- Time taken to stop the car .
So , here use first equⁿ of motion which is ,

where ,
- v is final Velocity.
- u is Initial velocity.
- a is acceleration.
- t is time taken.
Now , substituting the respective values ,






A. Because that is a digital balance
From Newton's law v^2 = u^2 + 2as where a is the acceleration and s is the distance.
But to go any further, we need to know how fast the vehicle is accelerating
From v = u +at
We have a = u/t where the final velocity v = 0
So in one minute acceleration = (35 / 60) / 60 = 0.0097 ms/2. The first
experession in bracket is the initial velocity, u, in metres per seconds.
Hence v^2 = (0.583)^2 + 2 (0.0097)(30)
v^2 = 0.3398 + 0.5826 = 0.9224
v = âš 0.9224 = 0.960m