1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leya [2.2K]
4 years ago
13

If the energy of the n = 1 state is E1 = 4 eV, after what time t does the wave function come back to the form described at t = 0

(apart from an arbitrary phase factor)?
Physics
1 answer:
zloy xaker [14]4 years ago
8 0

Answer:

The time is 3.4\times10^{-16}\ s

Explanation:

Given that,

Number of energy level n= 1

Energy E₁=4 eV

We need to calculate the time period

Using formula of time period

T=\dfrac{1}{f}

T=\dfrac{h}{E_{2}-E_{1}}

Where, E = energy

E_{2}=4E_{1}

h = Planck constant

Put the value into the formula

T=\dfrac{6.63\times10^{-34}}{4E_{1}-E_{1}}

T=\dfrac{6.63\times10^{-34}}{3E_{1}}

T=\dfrac{6.63\times10^{-34}}{3\times4\times1.6\times10^{-19}}

T=3.4\times10^{-16}\ s

Hence, The time is 3.4\times10^{-16}\ s

You might be interested in
Two identical traveling waves, moving in the same direction, are out of phase by π/5.0 rad. What is the amplitude of the resulta
andreev551 [17]

Answer:

Therefore the amplitude of the resultant wave is =0.95 y_m

Explanation:

The equation of wave:

y=A sin (kx-ωt)

For wave 1:

y₁=A sin (kx-ωt) = y_{m}sin (kx-ωt)

For wave 2:

y₂=A sin (kx-ωt+Φ) = y_{m}sin (kx-ωt+Φ)

Where A= amplitude=y_m

The angular frequency \omega=\frac{2\pi}{T}

k=\frac{2\pi}{\lambda} , \lambda= wave length.

t= time

T= Time period

\phi = phase difference =  \frac{\pi}{5}

The resultant wave will be

y = y₁ + y₂

 =y_m sin (kx-ωt) + y_m sin (kx-ωt+Φ)

 =y_m {sin (kx-ωt) + sin (kx-ωt+Φ)}

 =y_m\  sin(\frac{kx-\omega t +\phi + kx-\omega t }2)\ cos(\frac{kx-\omega t  +\phi -kx+\omega t}2)

 =y_m\  sin({kx-\omega t +\frac\phi 2)\ cos(\frac{\phi }2)

=y_m\ cos(\frac{\phi }2) sin({kx-\omega t +\frac\phi 2)

Therefore the amplitude of the resultant wave is

=y_m\ cos(\frac{\phi }2)

=y_m\ cos(\frac{\pi }{10})

=0.95 y_m

6 0
4 years ago
Will mark ask brainlest
kvv77 [185]

Answer:

woah yes

Explanation:

5 0
3 years ago
Read 2 more answers
How long will it take a car to go from a complete stop to 44 km/hr if they are accelerating at 5 km/hr?
Aleonysh [2.5K]

<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>

Given that ,

  • Initial Velocity of car = 44km / hr.
  • Final Velocity of car = 0km / hr.
  • Acceleration = -5km/hr².

To Find :

  • Time taken to stop the car .

So , here use first equⁿ of motion which is ,

\boxed{\red{\bf\dag v = u + at }}

where ,

  • v is final Velocity.
  • u is Initial velocity.
  • a is acceleration.
  • t is time taken.

Now , substituting the respective values ,

\tt:\implies v=u+at

\tt:\implies 0 = 44 + (-5)t

\tt:\implies -44 = -5t

\tt:\implies t=\dfrac{44}{5}

\underline{\boxed{\red{\tt \longmapsto Time\:\:=\:\:8.8hrs.}}}

\boxed{\green{\bf\pink{\dag} Hence\:time\:taken\:to\:stop\:the\:car\:is\:8.8hrs.}}

6 0
3 years ago
The purpose of this piece of equipment is to
frozen [14]
A. Because that is a digital balance
6 0
4 years ago
a canoe is floating down a river with a velocity of 35 meters per minute when it suddenly approaches a waterfall. if the waterfa
vampirchik [111]
From Newton's law v^2 = u^2 + 2as where a is the acceleration and s is the distance.  
But to go any further, we need to know how fast the vehicle is accelerating 
 From v = u +at
 We have a = u/t where the final velocity v = 0

 So in one minute acceleration = (35 / 60) / 60 = 0.0097 ms/2. The first
experession in bracket is the initial velocity, u, in metres per seconds. 
 Hence v^2 = (0.583)^2 + 2 (0.0097)(30)
 v^2 = 0.3398 + 0.5826 = 0.9224
 v = âš 0.9224 = 0.960m
3 0
3 years ago
Other questions:
  • What is wind or wind currents? I'm on that subject and don't get what it is. for the subject, I chose "Physics" because I don't
    5·2 answers
  • which has a greater kinetic energy a 20.0kg greyhound running at 16m/s or a 923.0kg polar bear running at 2.5m/s
    8·1 answer
  • How does the brightness of a bulb tell you about the energy of electrons passing through it?
    15·1 answer
  • A toy car is placed 29.0cm from a convex mirror. The image of the car is upright and one-sixth as large as the actual car. Calcu
    8·1 answer
  • This circle represents a wire running towards you. Using the right hand curl rule, in which direction is the magnetic field movi
    7·1 answer
  • The emf of a battery is equal to its terminal potential difference: A) under all conditions B) only when the battery is being ch
    10·2 answers
  • A cart of 8 kg mass has a force of 16 newtons exerted on it, what is its acceleration?
    13·1 answer
  • Plz answer fast need your help plz​
    6·1 answer
  • A spinning top completes 6.00x10^3 rotations before it starts to topple over. The average speed of the rotations is 8.00x10^2 rp
    10·1 answer
  • A student is provided with a battery-powered toy car that the manufacturer claims will always operate at a constant speed. The s
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!