Plz answer fast need your help plz

What is the angular position in radians of the minute hand of a clock at 2:55?

OleMash [197]

Refer to the diagram shown.

There are twelve 5-minute divisions.
Each 5-minute division is equal to 360°/12 = 30°.

By convention, angles are measured counterclockwise from the positive x-axis.
The angular position of the minute hand at 2:55 is
θ = 90° + 30° = 120°

Because 360° = 2π radians, therefore
θ = (120/360)*2π = (2π)/3 radians = 2.0944 radians

Answer: (2π)/3 radians ofr 2.0944 radians.

8 0

3 years ago

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The second Law of Thermodynamics states that: A. spontaneous processes are characterized by the overall conversion of order to d

Georgia [21]

Answer:

Spontaneous processes are characterized by the overall conversion of order to disorder.

Explanation:

The second law of thermodynamics states that: A spontaneous process occurs only if there is an increase in entropy of a system and its surroundings.

Entropy, S, is a measure of the randomness or disorder of a system. It is measured in J/Kmol.

The change in entropy, ∆S = ∆H/T

Where ∆H = change in enthalpy, T = Temperature in Kelvin.

For,

I. An endothermic reaction, ∆S = positive (that is, ∆S is greater than zero), there is an increase in entropy, therefore, the reaction is spontaneous.

II. An exothermic reaction, ∆S = negative (that is, ∆S is less than zero) there is a decrease in entropy, so, the reaction is non-spontaneous.

III. A system at equilibrium, ∆S = 0.

Then,

The standard change in entropy of a reaction, ∆So reaction , is the difference in the standard entropies between products and reactants:

∆So reaction = n ∆Soproducts - m ∆Soreactants

Where, = sigma = sum of,

∆ = delta = change in,

n and m = stoichiometric coefficients of the products and reactants respectively.

Furthermore, the entropy of the system and surroundings is referred to as the entropy of the universe.

∆Suniverse = ∆Ssurroundings + ∆Ssystem.

Processes leading to an increase in entropy include melting, heating, vaporization, dissolving.

8 0

3 years ago

In which direction are the winds blowing in the northern and southern hemispheres

Alika [10]

The winds normally blow from east to the west rather than blowing from the north to the south in the northern and the southern hemispheres.

Explanation:

The reason for the blowing of the wind from the east to the west rather than from the north to the south in both the hemispheres which are the northern and the southern hemispheres are because it happens in light of the fact that Earth's rotation around it's own axis creates what is known as the Coriolis effect.

The Coriolis impact makes wind frameworks turn counter-clockwise in the Northern Hemisphere and clockwise in the Southern Hemisphere.

6 0

3 years ago

What are cirrus.cirrostratus. And cirrocumulus clouds made up of

Irina-Kira [14]

1. All clouds are made up of tiny ice crystals or small water droplets that form together with a dust on the atmosphere.
Cirrus, cirrostratus and cirrocumulus are made up of ice crystals. It forms when the water vapor goes condensation at high altitudes in where the pressure on the atmosphere reaches the point from 600 mbar at 4000 meter above the sea level up to 200mbar at 12 000m above sea level. These clouds form thunderstorms, cyclones and contrails (a manmade cloud).

3 0

3 years ago

When a 2.60-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 2.86 cm. (a) W

Goryan [66]

Answer:

a) k = 891.82 N/m

b) e = 0.0143 m = 1.43 cm

c) W = 5.02 J

Explanation:

Step 1: Data given

Mass = 2.60 kg

the spring stretches 2.86 cm = 0.0286

Step 2: What is the force constant of the spring?

Force constant, k = force applied / extension produced

k = (2.60kg * 9.81N/kg) / 0.0326 m

k = 891.82 N/m

b) If the 2.60-kg object is removed, how far will the spring stretch if a 1.30-kg block is hung on it

Extension = F/k = (1.30 kg * 9.81) / 891.82 = 0.0143 m = 1.43 cm

Half the mass means half the extension

c) How much work must an external agent do to stretch the same spring 7.50 cm from its unstretched position?

W = average force used * distance

W = 1/2 * k*e * e = 1/2 k*e²

W = 1/2 * 891.82 * (0.075)² = W = 5.02 J

5 0

3 years ago

Plz answer fast need your help plz​

Plz answer fast need your help plz