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3 years ago

How does the brightness of a bulb tell you about the energy of electrons passing through it?

1 answer:

8 0

The brightness of the bulb doesn't tell you anything about the energy of the
electrons passing through it.

It tells you how much total energy is lost by the total flow of electrons through
the bulb. You can't tell what part of that is due to a large or small number of
electrons, or what part of it is due to each electron losing a large or small amount
of energy on the way through.

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How can you increase your cardio respiratory endurance

garik1379 [7]

Answer:

You can increase your cardio respiratory endurance by exercising on the regular base that increase your heart beat and breathing rates. Some examples of good exercise is running, jumping rope, swimming dancing ect.

Explanation:

You are welcome.

5 0

1 year ago

You pull on a spring whose spring constant is 22 N/m, and stretch it from its equilibrium length of 0.3 m to a length of 0.7 m.

Liono4ka [1.6K]

Answer:

W= 4.4 J

Explanation

Elastic potential energy theory

If we have a spring of constant K to which a force F that produces a Δx deformation is applied, we apply Hooke's law:

F=K*x Formula (1): The force F applied to the spring is proportional to the deformation x of the spring.

As the force is variable to calculate the work we define an average force

$F_{a} =\frac{F_{f}+F_{i} }{2}$ Formula (2)

Ff: final force

Fi: initial force

The work done on the spring is :

W = Fa*Δx

Fa : average force

Δx : displacement

$W = F_{a} (x_{f} -x_{i} )$ :Formula (3)

$x_{f}$ : final deformation

$x_{i}$ :initial deformation

Problem development

We calculate Ff and Fi , applying formula (1) :

$F_{f} = K*x_{f} =22\frac{N}{m} *0.7m =15.4N$

$F_{i} = K*x_{i} =22\frac{N}{m} *0.3m =6.6N$

We calculate average force applying formula (2):

$F_{a} =\frac{15.4N+6.2N}{2} = 11 N$

We calculate the work done on the spring applying formula (3) : :

W= 11N*(0.7m-0.3m) = 11N*0.4m=4.4 N*m = 4.4 Joule = 4.4 J

Work done in stages

Work is the change of elastic potential energy (ΔEp)

W=ΔEp

ΔEp= Epf-Epi

Epf= final potential energy

Epi=initial potential energy

$E_{pf} =\frac{1}{2} *k*x_{f}^{2}$

$E_{pi} =\frac{1}{2} *k*x_{i}^{2}$

$E_{pf} =\frac{1}{2} *22*0.7^{2} = 5.39 J$

$E_{pf} =\frac{1}{2} *22*0.3^{2} = 0.99 J$

W=ΔEp= 5.39 J-0.99 J = 4.4J

4 0

2 years ago

A block of wood measuring 2.75 cm x 4.80 cm x 7.50 cm has a mass of 84.0 g. will the block of wood sink or float in water?

KIM [24]

The volume of the block of wood is given by length × width ×height
= 2.75 × 4.80 × 7.5
= 99 cm³
Density is given by mass/volume
Thus = 84.0 g/ 99 cm³
= 0.848 g/cm³
Hence; since the block is less dense than water (1 g/cm³) it will float

6 0

2 years ago

What theory did dalton propose about the structure of matter

Irina-Kira [14]

Dalton’s atomic theory proposed that all matter was composed of atoms

8 0

3 years ago

Read 2 more answers

Wax, like all matter, comes in many phases. What are the three possible

Ivahew [28]

Answer:

A and d

Explanation:

Mixture and solid

5 0

2 years ago