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3 years ago

Will mark ask brainlest

Physics

2 answers:

kvv77 [185]3 years ago

5 0

Answer:

woah yes

Explanation:

Lubov Fominskaja [6]3 years ago

5 0

Its astroid one has more mass than astroid 2. I believe.

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Thank you in advance

Musya8 [376]

$m1 = \frac{- v2m2 - m2v1}{v2 - v1}$

8 0

3 years ago

The average intensity of light emerging from a polarizing sheet is 0.775 W/m2, and that of the horizontally polarized light inci

rewona [7]

Answer:

the transmission axis of polarizing sheet makes an angle of $\Theta =26.74^{\circ}$ with the horizontal

Explanation:

We have given that intensity of light incident on the sheet $I_0=0.970W/m^2$

Average intensity of light emerging from a polarizing sheet $I=0.775W/m^2$

We have to find the angle between transmission axis with the horizontal

Intensity of light polarizing from sheet is equal to $I=I_0cos^2\Theta$

So $0.775=0.970cos^2\Theta$

$cos^2\Theta =0.798$

$cos\Theta =0.893$

$\Theta =26.74^{\circ}$

So the transmission axis of polarizing sheet makes an angle of $\Theta =26.74^{\circ}$ with the horizontal

5 0

3 years ago

A uniform thin spherical shell of mass M=2kg and radius R=0.23m is given an initial angular speed w=18.3rad/s when it is at the

Rashid [163]

Answer:

47.8rad/s

Explanation:

For energy to be conserved.

The potential energy sustain by the object would be equal to K.E

P.E = m× g× h = 2 × 9.81× 3.5= 68.67J

Now K.E = 1/2 × I × (w1^2 - w0^2)

I = 2/3 × M × R2

= 2/3 × 2 × (0.23)^2= 0.0705

Hence

W1 = final angular velocity

Wo = initial angular velocity

From P.E = K.E we have;

68.67J = 1/2 × 0.0705 × (w1^2 - w0^2)

(w1^2 - w0^2) = 1948.09

W1^2 = 1948.09 + (18.3^2)

W1^2=2282.98

W1 = √2282.98

=47.78rad/s

= 47.8rad/s to 1 decimal place.

7 0

3 years ago

A 20 kg cart moving at 4 m/s has how much momentum?

masha68 [24]

Answer:

We conclude that the required momentum is 80 kgm/s.

Explanation:

Given

Mass m = 20 kg

Velocity v = 4 m/s

To determine

The momentum p = ?

Important Tip:

The momentum of an object is the product of mass and velocity.

We can determine the momentum using the formula

$p = mv$

where

p is the momentum

m is the mass

v is the velocity

now substituting m = 20 and v = 4 using the equation

$p = mv$

$p = (20) (4)$

$p = 80$ kg m/s

Therefore, we conclude that the required momentum is 80 kgm/s.

6 0

3 years ago

What is the momentum of a 0.122 kg baseball traveling at 39 m/s

Artyom0805 [142]

For the one I can do to make it to get my stuff ready for my

3 0

3 years ago

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