Answer:
, all integers where n≥1
Step-by-step explanation:
we know that
The explicit equation for an arithmetic sequence is equal to
a_n is the th term
a_1 is the first term
d is the common difference
n is the number of terms
we have

Remember that
In an Arithmetic Sequence the difference between one term and the next is a constant, and this constant is called the common difference.
To find out the common difference subtract the first term from the second term

substitute the given values in the formula

The domain is all integers for 
Answer:
the two numbers are 12 and -29
Step-by-step explanation:
let the two numbers be x and y
let the sum of the two numbers b
x+y = -17 ..................................................... equation 1
let the difference between the two numbers be
x-y = 41 ........................................................................ equation 2
from equation 1
x+y = -17 ..................................................... equation 1
x = -17 - y ............................................................... equation 3
substitute for x in equation 2
x-y = 41 ........................................................................ equation 2
-17-y -y = 41
-17 -2y = 41
-2y = 41 + 17
-2y = 58
divide both sides by -2
-2y/-2 = 58/-2
y = -29
put the value of y = -29 in equation 3
x = -17 - y ............................................................... equation 3
x = -17-(-29)
x =-17 + 29
x = 12
therefore the two numbers are 12 and -29
Answer: The required length of the segment AA' is 11 units.
Step-by-step explanation: Given that the point A(5, 11) is reflected across the X-axis.
We are to find the length of the segment AA'.
We know that
if a point (x, y) is reflected across X-axis, then its co-ordinates becomes (x, -y).
So, after reflection, the co-ordinates of the point A(5, 11) becomes A'(5, -11).
Now, we have the following distance formula :
The DISTANCE between two points P(a, b) and Q(c, d) gives the length of the segment PQ as follows :

Therefore, the length of the segment AA' is given by

Thus, the required length of the segment AA' is 11 units.
1 gallon = 16.8 miles
265 gallons = 16.8 x 265 = 4452 miles
Answer: 4452 miles