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3 years ago

Match each pair of equivalent fractions. 1 . 4/16 2 . 12/18 3 . 4/10 4 . 16/20

1 answer:

3 0

Basically divide each fraction to get the simplified version of each answer. You divide each fraction by the highest multiple.
4/16 can be divided by 4 to get 1/4
12/18 can be divided by 6 to get 2/3
4/10 can be divided by 2 to get 2/5
16/20 can be divided by 4 to get 4/5

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Kelly works two jobs. She usually works at a retail store for 7 hours during the day and is paid $22.22 per hour by the store. I

Ede4ka [16]

Answer:

Hey,

so if she works for seven hours at both jobs then we multiply how much she gets paid per hour times seven or 22.22*7=155.54 and 13.55*7=94.85. Then we add what is underlined, 155.54+94.85= our answer which is 250.39 per day.

Wbob1314 hope it helped

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3 years ago

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Factor completely. n ^4 - 1

inna [77]

(n^4 - 1) = (n^2 - 1) (n^2 +1) = (n - 1) (n + 1) (n^2 + 1)

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3 years ago

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100 POINTS! College Statistics

kirza4 [7]

(a) Collision claims tend to be skewed right because there are a few very large collision claims relative to the majority of claims.

These large collision claims skew the data to the right because they are outliers that draw the mean higher than it should be.

The answer cannot be "no large collision claims" or "many large collision claims" because then the data would not be skewed.

(b) Since there are two random samples comparing two means, we will be using a 2-Samp-T-Test. We will use Welch's approximate t-test, where we test the hypothesis that these two populations have the same mean.

We want to determine if 20-24 year old drivers have the same mean collision cost as 30-59 year old drivers.

(c) The null hypothesis is that the mean claim of collision costs for 20-24 year old drivers is the same as the mean claim of collision costs for 30-59 year old drivers.

We can also rewrite this as:

H₀: μ₁ = μ₂
where μ₁ is the mean collision claims for 20-24 year old drivers
and μ₂ is the mean collision claims for 30-59 year old drivers

The alternative hypothesis is that the mean claim of collision costs for 20-24 year old drivers is higher than the mean claim of collision costs for 30-59 year old drivers.

We can rewrite this as:

H₁: μ₁ > μ₂
Our variables have already been defined

(d) In order to calculate the p-value, we must find the test statistic first.

We can do so by using this formula:

$\displaystyle t=\frac{x_1-x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2} }}$

We are given these variables in the problem:

$x_1=4590$
$s_1=2302$
$x_2=3670$
$s_2=2029$
$n_1=40$
$n_2=40$

Substitute these variables into the formula for the test statistic.

$\displaystyle t=\frac{4590-3670}{\sqrt{\frac{2302^2}{40} +\frac{2029^2}{40} } }$

You can use the calculator to solve this expression, or plug the numbers into your calculator using: STAT - TESTS - 4:2-SAMPTTEST.

Your test statistic should be: t = 1.8962.

The calculator should also tell you the p-value; p = .0308.

(e) Since p = .0308 < α = .1, reject the null. We have convincing statistical evidence that the mean claim of collision costs for 20-24 year old drivers is higher than the mean claim of collision costs for 30-59 year old drivers.

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2 years ago

A survey handed out to individuals at a major shopping mall in a small Florida city in July asked the following: Gender Age Ethn

AysviL [449]

Answer and Explanation:

Gender data is categorical as it can be sorted into two categories - males and females - and does not involve any numerical values.

Age data is ratio as each person's age is a numerical value and it has a natural zero as point of origin. Moreover, the numerical values cannot be negative.

Ethnicity data is categorical as the various ethnicities to which those surveyed can belong are separate categories. There are no numerical values involved.

Length of residency data is ratio as the length duration is measured in number of years, thus having a numerical value. There is also a natural zero as point of origin and no possible negative values.

Overall satisfaction with city services data is ordinal as it is based on a ranking from poor to excellent.

Quality of schools data is also ordinal as it involves a ranking or definite ordering of data - from poor to excellent.

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3 years ago

PLEASE HELP!!! 9/10 divided by (-3/5) Write the answer as a mixed number

agasfer [191]

$\frac{\frac{9}{10}}{\frac{-3}{5}}=\frac{45}{-30}=-\frac{9}{6}=\boxed{\frac{3}{2}}$

Hope this helps.

r3t40

6 0

3 years ago