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3 years ago

Why are we not crushed by the weight of the atmosphere on our shoulders?

Physics

1 answer:

antiseptic1488 [7]3 years ago

5 0

Answer:

Due to equal pressure in all the direction at a particular level in a fluid medium (Pascal's Law)

Explanation:

We are not crushed by the weight of the atmosphere because atmosphere is a fluid and we are immersed into it. So, according to the Pascal's law the the pressure a each point in a horizontal level is equal in all the direction irrespective of the orientation of a body.

Variation of pressure in term of the height of a fluid medium is given as:

$P=\rho.g.h$

$\rho=$ density of fluid

g = acceleration due to gravity

h = height of the free surface of the fluid from the immersed object.

And atmosphere has very less variation of pressure with change in height as it is a rare medium fluid and so for a human height there is very negligible variation of pressure at the heat of a human with respect to his toe.

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Which statement best define energy

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"The capacity of a system to perform work of any type."

Explanation:

The best statement to describe Energy is:

"The capacity of a system to perform work of any type."

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Which statement supports the idea that the Earth rotates on its axis?

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B. A sandbar is formed by water. A sand dune is formed by wind.

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3 years ago

Assume that the energy lost was entirely due to friction and that the total length of the PVC pipe is 1 meter. Use this length t

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The question is incomplete. The complete question is :

Assume that the energy lost was entirely due to friction and that the total length of the PVC pipe is 1 meter. Use this length to compute the average force of friction (for this calculation, you may neglect uncertainties).

Mass of the ball : 16.3 g

Predicted range : 0.3503 m

Actual range : 1.09 m

Solution :

Given that :

The predicted range is 0.3503 m

Time of the fall is :

$t=\sqrt{\frac{2H}{g}}$

$v_1t= 0.35$ ...........(i)

$v_0t= 1.09$ ...........(ii)

Dividing the equation (ii) by (i)

$\frac{v_0t}{v_1t}=\frac{1.09}{035} = 3.11$

∴ $v_0=3.11 \ v_1$

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$W=\frac{1}{2} m [v_0^2-v_1^2]$

$W=\frac{1}{2} \times (16.3 \times 10^{-3}) \times [v_0^2-\left(\frac{v_0}{3.11}\right)^2]$

$W=7.307\times 10^{-3} \ v_0^2$

If f is average friction force, then

(f)(L) = W

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(f) = $7.307\times 10^{-3} \ v_0^2$

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3 years ago

A proton is projected in the positive x direction into a region of a uniform electric field →E =(-6.00 × 10⁵) i^ N/C at t=0 . Th

anzhelika [568]

The acceleration of the proton that is projected in the positive x direction into a region of a uniform electric field is 5.76×〖10〗^13 m/s^2

The product of the field's strength and the charge's strength yields the magnitude of the electric force acting on a charge traveling in a magnetic field region.

The electric force magnitude acting on the charge is expressed in the equation below.

F=|→E|×|q|

F=|-6.00×〖10〗^5 N/C|×||+1.602×〖10〗^(-19) C|

F=9.612×〖10〗^(-14) N

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a=F/m

Where F is the force and m is the mass;

Inserting the values into the equation,

a=(9.612×〖10〗^(-14) N)/(1.67×〖10〗^(-27) kg)

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Therefore, the acceleration of proton is 5.76×〖10〗^13 m/s^2 #SPJ4

brainly.com/question/13263306

#SPJ4

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1 year ago