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Andre45 [30]
4 years ago
11

Sometimes when you are training for event you may notice a decrease in improvement in level out of performance true or false

Physics
2 answers:
valina [46]4 years ago
8 0

Answer:

<h2>True.</h2>

Explanation:

When you are training to a performance, it's possible that you realise that you are not that good enough, or your performance is equal than before trainings. This could happen in a context where you are in a top point, and don't know how to keep improving.

blagie [28]4 years ago
3 0
<span>Sometimes when you are training for event you may notice a decrease in improvement in level out of performance. T</span>rue 

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What is the position of the earth, moon, and sun during a new moon?
svetlana [45]

The Moon always rotates about the Earth in its orbit. The position of the Earth, moon and sun during a new moon is Earth is in between Sun and Moon.

<h3>What is new moon?</h3>

When moon has travelled for 14 days, it starts its journey again for the next 14 days. The journey starts from the new moon to the full moon. The position of new and full moon is the same. At this time, the Earth is in between the Sun and the Moon.

Thus, the position of the Earth, moon and sun during a new moon is Earth is in between Sun and Moon.

Learn more about New Moon.

brainly.com/question/13538936

#SPJ2.

8 0
2 years ago
Read 2 more answers
Large bodies of water help to keep nearby climates from being too hot or too cold because they
Ludmilka [50]
Large bodies of water help to keep nearby climates from being too hot or too cold because they absorb heat in the summer and slowly release that heat in the winter.

So your answer is absorb
7 0
4 years ago
. Newton's law of gravity describes the gravitational force between __________.
Svetllana [295]

Answer:

a.All of the listed answers are correct.

Explanation:

Newton's law of universal gravitation states two bodies attract each other with a force directly proportional to the square of their masses and inversely proportional to the square of the distance that separates them, and is directed along the line that joins the bodies. This force is known as the force of gravity or gravitational force and is expressed as:

F=G*\frac{m_1 *m_2}{r^2}

Where:

m_1\hspace{3}and\hspace{3}m_2= Masses\hspace{3}of\hspace{3}the\hspace{3}objects\\G= Gravitational\hspace{3}constant\\r=Distance\hspace{3}between\hspace{3}the\hspace{3}objects

Therefore, the gravitational interaction between two bodies always manifests as a pair of equal forces in direction and magnitude but in the opposite direction.

7 0
3 years ago
Is the amount of friction greater between rough surfaces or smooth surfaces? Why?
nalin [4]

Answer:

friction occurs because no surface is perfectly smooth.

Explanation:

rougher surfaces have more friction between them.

6 0
3 years ago
A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75
8_murik_8 [283]

Complete Question

A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75.0 cm . The power is off for 40.0 s , and during this time the flywheel slows down uniformly due to friction in its axle bearings. During the time the power is off, the flywheel makes 210 complete revolutions. At what rate is the flywheel spinning when the power comes back on(in rpm)? How long after the beginning of the power failure would it have taken the flywheel to stop if the power had not come back on, and how many revolutions would the wheel have made during this time?

Answer:

\theta=274rev

Explanation:

From the question we are told that:

Angular velocity \omega=510rpm

Mass m=40.kg

Diameter d 75=>0.75m

Off Time t=40.0s

Oscillation at Power off N=210

Generally the equation for Angular displacement is mathematically given by

 \theta_{\infty}=\frac{w+w_0}{t}t

 w=\frac{2*\theta_{\infty}}{t}-w_0

 w=\frac{28210}{40*(\frac{1}{60})}-510

 w=120rpm

Generally the equation for Time to come to rest is mathematically given by

 t=(\frac{\omega_0}{\omega_0-\omega})t

 t=(\frac{510}{510-120rpm})(40.0)(\frac{1}{60})

 t=0.87min

Therefore Angular displacement is

 \theta =(\frac{120+510}{2})0.87

 \theta=274rev

6 0
3 years ago
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