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borishaifa [10]
3 years ago
6

Assume that the blocks are accelerating, and the x components of their accelerations at a certain moment are a1x and a2x. find t

he x component of the acceleration of the center of mass (acm)x at that moment. keep in mind that, in general, ax=dvx/dt. express your answer in terms of m1, m2, a1x, and a2x.
Physics
2 answers:
goldfiish [28.3K]3 years ago
6 0

The amount of movement may be a product of body mass due to its speed, its speed is that the center of mass; The equation is:

p = mv

Where v is that the velocity of the middle of the body mass, all we've got to try and do is rate the rate

V = p / m

This is our case for everyone and since the number of motion may be a vector, we must write it for every axis

V1x = p1x / m1

V2x = p2x / m2

<h2>Further Explanation </h2>

The speed of motion is a vector quantity that shows how fast an object is moving. Speed ​​can also mean speed that has direction. Speed ​​(Speed) is the ability to move the body from one place to another in the shortest possible time.

Regular Straight Motion (RSM) is a straight motion that has a constant speed. Then the acceleration value is a = 0. RSM motion is linear and the velocity value is the result of the distance with the time taken.

Straight motion changes irregularly are motion whose trajectory is in the form of a straight line with irregularly changing speed. The acceleration is constant.

Objects are thrown vertically, perpendicular to the horizontal plane up with a certain initial velocity. The direction of motion of objects and the direction of acceleration of gravity are opposite, straight-motion changes irregularly slowed.

Learn More

Speed of Motion  brainly.com/question/11657015

The Amount of Movement  brainly.com/question/11657015

Details

Grade: College

Subject: Physics

Keyword: motion, speed, movement

Serga [27]3 years ago
3 0

we know that center of mass is given as

r = (m₁ r_{1x} + m₂ r_{2x})/(m₁ + m₂)

taking derivative both side relative to "t"

dr/dt = (m₁ dr_{1x}/dt + m₂ dr_{2x}/dt)/(m₁ + m₂)

v = (m₁ v_{1x} + m₂ v_{2x})/(m₁ + m₂)

taking derivative again relative to "t" both side

dv/dt = (m₁ dv_{1x}/dt + m₂ dv_{2x}/dt)/(m₁ + m₂)

a= (m₁ a_{1x} + m₂ a_{2x})/(m₁ + m₂)

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Answer:

d) 289.31 m

Explanation:

Energy provided by potential energy = mgh = m x 9.8x 200 sin10.5 = 357.18m

Energy used by friction = μmgcos 10.5 x 200 = .075 x m x 9.8 x cos 10.5 x200 = 144.54 m .

Energy used by friction on plain surface = μmg x d.( dis distance covered on plain ) =.075x m x 9.8 xd = .735 m d

To equate

357.18 m -144.54 m = .735 m d

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4 0
3 years ago
A number is written in scientific notation when it is the product of a number less than 10 but greater than or equal to 1 and a
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Answer:

Mass = 1.99 * 10^{30} kg

Explanation:

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Mass = 1,990,000,000,000,000,000,000,000,000,000\ kg

Required

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7 0
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6 0
3 years ago
1. A 4000-kg truck traveling with a velocity of 20 m/s due south collides headon with a 1350-kg car traveling with a velocity of
velikii [3]

(a) The momentum of each vehicle prior to collision is 80000 kgm/s for truck and 13500 kgm/s for car.

(b) The size of momentum is 93500 kgm/s and it will be directed towards South.

Explanation:

The mass of the truck moving due south is given as 4000 kg and the speed is 20 m/s. Similarly, the mass of the car moving due north is 1350 kg and the speed is 10 m/s.

(a) Then the momentum of each vehicle can be obtained by the product of mass with their respective speed.

Momentum of truck = Mass * Speed = 4000 * 20 =80000  kgm/s

Similarly, the momentum of car will be

Momentum of car = 1350 * 10 = 13500 kgm/s

So, the momentum of each vehicle prior to collision is 80000 kgm/s for truck and 13500 kgm/s for car.

(b) Since, after collision, the vehicles stick together, the momentum after collision will be equal to the total momentum of both the vehicles before collision. This is because, it will obey conservation of momentum.

Momentum of vehicles after collision = total momentum before collision

Momentum after collision = 80000+13500 = 93500 kgm/s.

The direction of the vehicles after collision will be towards south as the mass and speed of the truck is greater than car. So the impact or force exerted on the car by the truck will be greater and thus both the vehicles will be directed towards south after collision.

Thus, the size of momentum is 93500 kgm/s and it will be directed towards South.

4 0
3 years ago
James gently releases a ball at the top of a slope But does not push the ball. Space the ball rolls down the slope. Which force
NARA [144]
On an incline, the force causing the ball to move downwards would be gravity. Additionally, the component of gravity causing this ball to move downwards would be mgsintheta.

Hope this helps!
7 0
3 years ago
Read 2 more answers
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