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borishaifa [10]
3 years ago
6

Assume that the blocks are accelerating, and the x components of their accelerations at a certain moment are a1x and a2x. find t

he x component of the acceleration of the center of mass (acm)x at that moment. keep in mind that, in general, ax=dvx/dt. express your answer in terms of m1, m2, a1x, and a2x.
Physics
2 answers:
goldfiish [28.3K]3 years ago
6 0

The amount of movement may be a product of body mass due to its speed, its speed is that the center of mass; The equation is:

p = mv

Where v is that the velocity of the middle of the body mass, all we've got to try and do is rate the rate

V = p / m

This is our case for everyone and since the number of motion may be a vector, we must write it for every axis

V1x = p1x / m1

V2x = p2x / m2

<h2>Further Explanation </h2>

The speed of motion is a vector quantity that shows how fast an object is moving. Speed ​​can also mean speed that has direction. Speed ​​(Speed) is the ability to move the body from one place to another in the shortest possible time.

Regular Straight Motion (RSM) is a straight motion that has a constant speed. Then the acceleration value is a = 0. RSM motion is linear and the velocity value is the result of the distance with the time taken.

Straight motion changes irregularly are motion whose trajectory is in the form of a straight line with irregularly changing speed. The acceleration is constant.

Objects are thrown vertically, perpendicular to the horizontal plane up with a certain initial velocity. The direction of motion of objects and the direction of acceleration of gravity are opposite, straight-motion changes irregularly slowed.

Learn More

Speed of Motion  brainly.com/question/11657015

The Amount of Movement  brainly.com/question/11657015

Details

Grade: College

Subject: Physics

Keyword: motion, speed, movement

Serga [27]3 years ago
3 0

we know that center of mass is given as

r = (m₁ r_{1x} + m₂ r_{2x})/(m₁ + m₂)

taking derivative both side relative to "t"

dr/dt = (m₁ dr_{1x}/dt + m₂ dr_{2x}/dt)/(m₁ + m₂)

v = (m₁ v_{1x} + m₂ v_{2x})/(m₁ + m₂)

taking derivative again relative to "t" both side

dv/dt = (m₁ dv_{1x}/dt + m₂ dv_{2x}/dt)/(m₁ + m₂)

a= (m₁ a_{1x} + m₂ a_{2x})/(m₁ + m₂)

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Tenemos.

Masa de la mesa = 20kg
Masa encima = 10kg
Masa total = 30kg
Area de cada pata = 20cm² = 20cm² * 1/10000cm² * 1m² =0,002m²

Presió(P)n que se ejerce sobre cada pata.

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