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asambeis [7]
3 years ago
6

1) A train accelerates from 36 km/hr to 54 km/hr in 10 s. Find acceleration?

Physics
1 answer:
Crank3 years ago
3 0

Answer: Given:

Initial velocity= 36km/h=36x5/18=10m/s

Final velocity =54km/h=54x5/18=15m/s

Time =10sec

Acceleration = v-u/ t

=15-10/10=5/10=1/2=0.5 m/s2

Distance =s=?

From second equation of motion:

S=ut +1/2 at^2

=10*10+1/2*0.5*10*10

=100+25

=125m

So distance travelled 125m

Hope it helps you

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Answer:

This galaxy belongs to the elliptical galaxy category. This is because it does not have spiral arms.

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2 years ago
What is the slope of the line plotted below? (-2,-1) (4,2) A. 1 B. 2 C. -0.5 D. 0.5
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Answer: D. 0.5

Explanation:

The slope formula is y2-y1/x2-x1.

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8 0
3 years ago
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Arace car accelerates uniformly at 11.3 m/s2. If the race car starts from rest how fast will it
Ganezh [65]

Answer:

75.71 m/s

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From equation of motion, acceleration is given by

a=\frac {v-u}{t}where v is the final velocity, u is the initial velocity and t is time taken.

Making v the subject of the above formula

v=at+u

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7 0
3 years ago
The tallest Ferris wheel in the world is located in Singapore. Standing 42 stories high and holding as many as 780 passengers, t
kakasveta [241]

Answer:

The speed of the riders on the Singapore Flyer is approximately 0.262 m/s

Explanation:

The dimensions of the tallest Ferris wheel in the world are;

The diameter of the Ferris wheel, D = 150 m

The tine it takes the Ferris wheel to make a full circle, T = 30 minutes = 30 min × 60 s/min = 1,800 seconds

The angular velocity of the Ferris wheel, ω = 2·π/T

The linear velocity of the Ferris wheel, v = r·ω = The speed of the riders

Where;

r = The radius of the Ferris wheel = D/2

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∴ r = 150 m/2 = 75 m

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The speed of the riders on the Singapore Flyer, v ≈ 0.262 m/s

8 0
3 years ago
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