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asambeis [7]
3 years ago
6

1) A train accelerates from 36 km/hr to 54 km/hr in 10 s. Find acceleration?

Physics
1 answer:
Crank3 years ago
3 0

Answer: Given:

Initial velocity= 36km/h=36x5/18=10m/s

Final velocity =54km/h=54x5/18=15m/s

Time =10sec

Acceleration = v-u/ t

=15-10/10=5/10=1/2=0.5 m/s2

Distance =s=?

From second equation of motion:

S=ut +1/2 at^2

=10*10+1/2*0.5*10*10

=100+25

=125m

So distance travelled 125m

Hope it helps you

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