Answer:
d) It will be cut to a fourth of the original force.
Explanation:
The magnitude of the electrostatic force between the charged objects is
where
k is the Coulomb's constant
q1 and q2 are the charges of the two objects
r is the separation between the two objects
In this problem, the initial distance is doubled, so
r' = 2r
Therefore, the new electrostatic force will be
So, the force will be cut to 1/4 of the original value.
- The net force is greatest at the position of maximum displacement
- The net force is zero when at the equilibrium position
Explanation:
The motion of a spring is a Simple Harmonic Motion, in which the displacement of the end of the spring is given by a periodic function of the form
where A is the amplitude (the maximum displacement), and the angular frequency of the motion.
We can analyze the net force acting on the spring by looking at Hooke's law:
where
F is the net force
k is the spring constant
x is the displacement
From the equation, we notice immediately that:
Learn more about forces:
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