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3 years ago

Whats the speed of darkness?

1 answer:

3 0

The same speed of light, the fastest possible

darkness is just the absence of light therefore once light leaves darkness returns. making darkness have the same speed of light

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Explain how the velocity of an object changes in respect to time.

blondinia [14]

Answer:

Is this your ans of this question

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4 years ago

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Compare the time period of two simple pendulums of length 4m and 16m at a place.

Vlad1618 [11]

Answer:

the period of the 16 m pendulum is twice the period of the 4 m pendulum

Explanation:

Recall that the period (T) of a pendulum of length (L) is defined as:

$T=2\,\pi\,\sqrt{ \frac{L}{g} }$

where "g" is the local acceleration of gravity.

SInce both pendulums are at the same place, "g" is the same for both, and when we compare the two periods, we get:

$T_1=2\,\pi\,\sqrt{\frac{4}{g} } \\T_2=2\,\pi\,\sqrt{\frac{16}{g} } \\ \\\frac{T_2}{T_1} =\sqrt{\frac{16}{4} } =2$

therefore the period of the 16 m pendulum is twice the period of the 4 m pendulum.

5 0

3 years ago

Scarcity exists because there are limited resources to meet unlimited wants and needs. true or false.

Sedbober [7]

The answer is true. scarcity exists because the resources are being depleted to meet the increasing demands of the people

6 0

3 years ago

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At the instant the traffic light turns green, an automobile starts with a constant acceleration a of 2.70 m/s2. At the same inst

kifflom [539]

Answer:

66.85 m

Explanation:

We are given that

Acceleration ,a= $2.7m/s^2$

Speed of truck, v=9.5 m/s

We have to find the distance beyond which the traffic signal will the automobile overtake the truck.

Initial speed of automobile, u=0

We know that

$s=ut+\frac{1}{2}at^2$

Using the formula

$s=0+\frac{1}{2}(27)t^2=\frac{27}{2}t^2$

For constant speed

Acceleration, a=0

Again

$s=vt+0=9.5t$

$9.5t=\frac{27}{2}t^2$

$t=\frac{9.5\times 2}{2.7}=7.037s$

Substitute the value of t

$x=9.5(7.037)=66.85m$

Hence, the distance beyond which the traffic signal will the automobile overtake the truck=66.85 m

3 0

3 years ago

A current of 3A passes through a 2.05cm diameter copper wire. if the wire has 8.5x1028 free electrons per cubic meter. How many

liberstina [14]

Answer:

For copper, ρ = 8.93 g/cm3 and M = 63.5 g/mol. Assuming one free electron per copper atom, what is the drift velocity of electrons in a copper wire of ...

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Explanation:

3 0

2 years ago

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