For this case we have the following kinematic equation that models the problem: h (t) = (1/2) * (- 9.8) * t ^ 2 + 12 * t + 2 Rewriting we have: h (t) = -4.9 * t ^ 2 + 12 * t + 2 When the ball hits the ground we have: -4.9 * t ^ 2 + 12 * t + 2 = 0 Solving the polynomial we have: t1 = -0.16 t2 = 2.61 We ignore the negative root because it is time. Answer: It will take the ball to hit the ground about: t = 2.61 sec