It is 0.5 because 1/2 x 1 is 0.5
Perimeter of the carpet = 21.8 m
Area of the carpet = 
<u>Given</u>:
<em>Dimension of the living room:</em>
<em />
<em>A. </em><em>Perimeter </em><em>of the carpet = perimeter of a </em><em>rectangle</em>
Perimeter = 
Substitute

Perimeter of the carpet = 21.8 m (The digits here are significant)
<em>B. </em><em>Area </em><em>of the carper = </em><em>area </em><em>of a </em><em>rectangle </em>
Area = 
Substitute

Area of the carpet =
(the digits here are significant)
Therefore, considering the rules of significant digits:
Perimeter of the carpet = 21.8 m
Area of the carpet = 
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Answer:
Number 1, i think
Step-by-step explanation:
Answer: First option is correct.
Step-by-step explanation:
Since we have given that

We will use law of exponents :

So, the simplified form is

Hence, First option is correct.