The total number of students is 14+36, or 50. So the chance that a selected student is female is 36/50, or 18/25.
In expanded form, it would be 9*10 + 5*1 + 4 * 0.1 + 1 * 0.01 + 7 * 0.001. Hope this helps!
Carl is incorrect. Dave ate a higher fraction of snack bars, by 0.2 snack bars.
Carl had .5 left of a snack bar.
Dave had .3 left of a snack bar.
Tony had .5 left of a snack bar.
Gary had .0 left of a snack bar.
Tryone had .7 left of a snack bar.
If we add the above snack bars, there is a total of two remaining snack bars, meaning they only ate 12 of 14 snack bars.
Answer:
27.4
Step-by-step explanation:
First multiply the numerator and denominator by 10
Then write the problem in long division format
Then divide 52 by 19 and get 2
Then multiply the quotient digit (2) by the divisor 19
Then subtract 38 from 52
Then bring down the next number of the dividend
Then divide 140 by 19 to get 7
Then multiply the quotient digit (7) by the divisor 19
Then subtract 133 from 140
Then add a decimal point to the solution
Then bring down the next number of the dividend
Then divide 76 by 19 to get 4
Then multiply the quotient digit (4) by the divisor 19
Then subtract 76 from 76
The solution for long division for 52.06./1.9 is 27.4
27.4
