3 years ago

Pleas help me for make sure the Second Question

Mathematics

1 answer:

fenix001 [56]3 years ago

4 0

The angles would be in ratio to each other, silly goose. :P

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Answer:

1) $sin^{-1}(\frac{1}{\sqrt{2} })=45$

2) $cos^{-1}(\frac{\sqrt{3} }{2})=30$

3) $tan^{-1}(\sqrt{3})=60$

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Step-by-step explanation:

1) Value of $sin^{-1}(\frac{\sqrt{2} }{2}) =sin^{-1}(\frac{1}{\sqrt{2} })$

since sin45° = 1/√2

Therefore $sin^{-1}(\frac{1}{\sqrt{2} })=45$

2).Value of $cos^{-1}(\frac{\sqrt{3} }{2})$

Since cos 30° = √3/2

Therefore $cos^{-1}(\frac{\sqrt{3} }{2})=30$

3). Value of $tan^{-1}(\frac{3}{\sqrt{3} }) = tan^{-1}(\sqrt{3})=60$

since tan 60° = √3

therefore $tan^{-1}(\sqrt{3})=60$

4). Value of $sin^{-1}(1)$

Since sin90°=1

Therefore $sin^{-1}(1)=90$

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Step-by-step explanation:

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